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Citrus2011 [14]

2 years ago

12

I know its easy but i forgot how to do this pls heeeelp me

1 answer:

denis23 [38]2 years ago

4 0

Answer:

First number line: 3rd line from 0

Second number line: 7th line from 0

(Sorry if I explained it kinda weird, hope this helps!)

Step-by-step explanation:

On the first number line, you would put the dot on the 3rd line from zero. From 0 to one, it's split into 5 equal parts. 0 is 0/5 and 1 is 5/5. So all you do is plot the dot on 3/5, or the 3rd line from 0.

Same thing with the second number line. Except for this time, it's split into 8 equal parts. Just count to the 7th line in between 0 and 1 and plot the dot.

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grandymaker [24]

Answer:

The Answer is is option B.

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2 years ago

Name the property used in each equation. Then find the value of n.

Pavlova-9 [17]

The answer is 5 and associative property

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2 years ago

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Kaylis [27]

Answer:

option A is the answer hope you find it helpful

3 0

2 years ago

Make g the subject of this relation

zhannawk [14.2K]

Answer:

see explanation

Step-by-step explanation:

Simplify the radical

$\frac{U}{\frac{1}{f}+\frac{1}{g} }$

= $\frac{U}{\frac{g+f}{fg} }$

= $\frac{Ufg}{g+f}$

Square both sides

T² = $\frac{Ufg}{g+f}$ ( multiply both sides by (g + f) )

T²(g + f) = Ufg ( distribute left side )

T²g + T²f = Ufg ← subtract Ufg from both sides

T²g - Ufg + T²f = 0 ← subtract T²f from both sides

T²g - Ufg = - T²f ← factor out g from each term on the left side

g(T² - Uf) = - T²f ← divide both sides by (T² - Uf)

g = - $\frac{T^2f}{T^2-Uf}$ = $\frac{T^2f}{Uf-T^2}$

6 0

2 years ago

The midpoint of AB is M (2,0). If the coordinates of A are, (-3, 3), what are the coordinates of B?

gregori [183]

Given:

M is the midpoint of AB.

M(2,0) and A(-3, 3).

To find:

The coordinates of point B.

Solution:

Midpoint formula:

$Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)$

Let the coordinates of point B are (a,b). Then, using the midpoint formula, we get

$(2,0)=\left(\dfrac{-3+a}{2},\dfrac{3+b}{2}\right)$

On comparing both sides, we get

$\dfrac{-3+a}{2}=2$

$-3+a=2\times 2$

$a=4+3$

$a=7$

And,

$\dfrac{3+b}{2}=0$

$3+b=0$

$3+b-3=0-3$

$b=-3$

Therefore, the coordinates of point B are (7,-3).

5 0

2 years ago