Answer:
What is P(A), the probability that the first student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)
What is P(A), the probability that the first student is a girl? (3/4)What is P(B), the probability that the second student is a girl? (3/4)What is P(A and B), the probability that the first student is a girl and the second student is a girl? (1/2)
The probability that the first student is a girl is (3/4), likewise for the 2nd 3rd and 4th it's still (3/4). The order you pick them doesn't matter.
However, once you're looking at P(A and B) then you're fixing the first position and saying if the first student is a girl what's the probability of the second student being a girl.
Answer:
112 in^2
Step-by-step explanation:
10 x 10 = 100
4 x 6 / 2 = 12
112 inches squared
<h3>
Answer:</h3>
D) 4 cm, 3 cm
<h3>
Step-by-step explanation:</h3>
Let x represent the length of "another" side. Then "one side" can be represented by (2x -5 cm).
The perimeter of the kite is the sum of two sides of each length:
... P = 14 cm = 2(x) + 2(2x -5 cm)
Dividing by 2 and collecting terms, we have ...
... 7 cm = 3x -5 cm
... 12 cm = 3x
... 4 cm = x . . . . the length of "another" side
... 2(4 cm) -5 cm = 3 cm . . . . the length of "one side"
The two different side lengths are 4 cm and 3 cm.
Median is the middle number. To find median, the numbers must be ordered from least to greatest. The numbers are already ordered.
The middle numbers are 36 and 55, with 2 numbers on each side.
a, b, c, d, e, f
Add the 2 numbers and divide by 2
Now divide by 2
The median is 45.5
Use the squeeze theorem; if
1 - <em>x</em> ²/4 ≤ <em>u(x)</em> ≤ 1 + <em>x</em> ²/2,
then taking the limit on each part as <em>x</em> approaches 0 gives
1 ≤ lim [<em>x</em> → 0] <em>u(x)</em> ≤ 1
and so the limit of <em>u(x)</em> as <em>x</em> → 0 is simply 1.
