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Novosadov [1.4K]
3 years ago
8

Select all expressions that are equivalent to 5x + (x+6) +3x.

Mathematics
1 answer:
zhuklara [117]3 years ago
6 0

Answer:

9x + 6 and 6x + 6 + 3x

Step-by-step explanation:

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Given f(x) = x3 – 2x2 – x + 2, the roots of f(x) are
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You have the following expression given in the problem:

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 0 </span><span>= x3 – 2x2 – x + 2

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3 years ago
solve the problem related to population growth.A city had a population of 23,900 in 2007 and a population of 25,100 in 2012.(a)
Finger [1]

Solution

a)

To find the exponential growth function, we apply the exponential growth formula which is

N(t)=a(1+k)^t

Where

\begin{gathered} a\text{ is the }initial\text{ population} \\ k\text{ is the growth rate} \\ t\text{ is the number of time intervals} \end{gathered}

Given that

\begin{gathered} a=23,900 \\ N(5)=25,100 \\ t=2012-2007=5 \end{gathered}

Substitute the variables into the exponential growth formula

\begin{gathered} 25100=23900(1+k)^5 \\ \text{Divide both sides by 23,900} \\ \frac{25100}{23900}=\frac{23900(1+k)^5}{23900} \\ 1.05021=(1+k)^5^{} \\ \sqrt[5]{1.05021}=1+k \\ 1.00984=1+k \\ \text{Collect like terms} \\ k=1.00984-1 \\ k=0.00984 \end{gathered}

Hence, the exponential growth function is

\begin{gathered} N(t)=23900(1+0.00984)^t_{} \\ N(t)=23900(1.00984)^t \end{gathered}

Hence, the exponential growth function is

N(t)=23900(1.00984)^t

b)

For the population of the city in 2022,

\begin{gathered} t=2022-2007=15 \\ t=15 \end{gathered}

Substitute for t into the exponential growth function

\begin{gathered} N(t)=23900(1.00984)^t \\ N(15)=23900(1.00984)^{15} \\ N(15)=27700\text{ (nearest hundred)} \end{gathered}

Hence, the population is 2022 is 27700 (nearest hundred)

8 0
1 year ago
Pls help me graphing this, pleaseee 20 points!!
sdas [7]

Answer:

Step-by-step explanation:  the first number goes two the side and the secend goes up

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