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GaryK [48]
2 years ago
14

What factors do 6 and 12 have in common?

Mathematics
1 answer:
ZanzabumX [31]2 years ago
8 0

Answer:

6x^2 im pretty sure thats whats its asking for

Step-by-step explanation:

You might be interested in
Which sum of difference is equivalent to the following expression? 5-3x/5
Aleks04 [339]

Answer:

1-3x/5

Give me brainiest

Step-by-step explanation:

7 0
2 years ago
1. Write the following radicals in simplest form<br> a) -3√288<br><br><br><br> b) 5√320
jeka57 [31]
A) -3√288=-3√(144*2)=-3√144<span>√2=-3*12</span><span>√2=-36</span><span>√2

b) </span>5√320=5<span>√(64*5)=</span>5<span>√64</span><span>√5=5*8</span><span>√5=40</span><span>√5</span>
8 0
2 years ago
1. 2x + 4 = 3(x – 2) + 1
sweet [91]
Please, do not post more than 1 or 2 questions at a time.  Out of courtesy I will address one of your six questions here:

<span>2x + 4 = 3(x – 2) + 1

You are to solve this for x.

1) perform the multiplication:     </span><span>2x + 4 = 3x - 6 + 1
2) combine like terms:                4+6-1 = x
3) solve for x:                              x = 11
4) check:  Is 2(11) + 4 = 3(11-2) + 1 true?
   Is 22+4 = 33-6 true?  NO.  Try again, looking for the mistake:

</span><span>2x + 4 = 3(x – 2) + 1  =>   2x + 4 = 3x - 6 + 1
                                                  4 = x - 5
                                                  9 = x

Check:  Is 2(9) + 4 = 3(9-2) + 1 true?  Is 18+4 = 22 true?  YES.
The solution to #1 is  x = 9  (answer).

Submit your other questions separately, please.

</span>
8 0
3 years ago
8/10 is iqual to 4/5
yan [13]
Yes, that is correct because if you want to reduce it you divide 8 by 2 and 10 by 2 and you get 4/5
5 0
3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=24x%5E%7B2%7D%2Bbx%5E%7B2%7D%20%3D25x%5E%7B2%7D" id="TexFormula1" title="24x^{2}+bx^{2} =25x^{
Liula [17]

Answer:

x = 0

Step-by-step explanation:

Subtract 25x^2 from both sides

24x^2 + bx^2 - 25x^2 - 25x^2

Simplify

bx^2 - x^2 = 0

Factor bx^2 - x^2: x^2(b - 1)

bx^2 - x^2

Factor out common term x^2

= x^2 (b - 1)

x^2(b - 1) = 0

Using the Zero Factor Principle: If ab = 0 then a = 0 or b = 0

x^2 = 0

Apply rule x^n = 0   x = 0

x = 0

8 0
2 years ago
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