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tamaranim1 [39]
3 years ago
13

Which inequality is shown above?

Mathematics
1 answer:
victus00 [196]3 years ago
8 0
The answer is C.

It’s a solid line so you know it has to be an inequality with a “or equal to” sign. Which leaves you with B or C. Find a point that isn’t on the line to test, use origin to make it simple. Plug it in for the x and y values. So 0 is greater than it equal to 0 - 3 which is -3. 0 is greater than -3 which means C is correct.
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Step-by-step explanation:

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<u><em>Could I please have BRAINLIEST.</em></u>

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Answer:

Step-by-step explanation:

(f*g)(x) = (-5x² + 2x + 7) (x +1)

          = x* (-5x² + 2x + 7) + 1*(-5x² + 2x + 7)

          = x*(-5x²) + x*2x + x*7 - 5x² + 2x + 7

        = -5x³ + 2x² + 7x - 5x² + 2x + 7

        = - 5x³ + <u>2x² -5x²</u>   <u>+ 7x + 2x </u>+7   {Combine like terms}

       =  -5x³ - 3x² + 9x + 7

4) (f*g)(x) = (x² + 2x + 4)(x - 2)

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                = x*x² + x*2x + x*4 - 2*x² - 2*2x -2* 4

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2) Speed=\dfrac{distance}{time}\\\\\\= \dfrac{d(h)}{t(h)}\\\\= \dfrac{2\sqrt{h}}{3\sqrt{4h}}=\dfrac{2*\sqrt{h}}{3*2\sqrt{h}}\\\\\\=\dfrac{1}{3}

1)d(h) = \sqrt{16h^{4}}=\sqrt{2*2*2*2*h*h*h*h}=2*2*h*h=4h^{2}\\\\\\t(h) = 3h^{4}-3h^{3}-5h^{2}= h^{2}(3h^{2}-3h - 5))\\\\Speed=\dfrac{4h^{2}}{h^{2}(3h^{2}-3h-5)}\\\\=\dfrac{4}{3h^{2}-3h-5}

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melamori03 [73]

Please view my other solution I gave you.

:)


But I will still answer this if you see it.

Because 0.8^x is never 0, then the asymptote is 0-10 or -10.

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