Answer:
Since both equations are equal to y, we can set them equal to each other.
y =-3x +8
y = -5x -2
-3x +8 = -5x -2
Solve for x.To do this, we need to get x by itself. First, move all the numbers to one side of the equation, and all the variables to the other.
-3x +8 = -5x -2
Add 5x to both sides
-3x+5x +8=-5x+5x -2
2x+8=-2
Subtract 8 from both sides
2x+8-8 = -2-8
2x=-10
Now, all the numbers are on one side, with the variables on the other. x is not by itself, it is being multiplied by 2. To undo this, divide both sides by 2
2x/2= -10/2
x= -5
Now, to find y, substitute -5 in for x in one of the equations.
y = -5x -2
y= -5(-5) -2
y=25-2
y=23
Put the solution into (x,y)
<u><em>The solution is (-5, 23)</em></u>
Let the number be x, therefore, its square is x², and 44 more than the number is x+44 whose square is (x+4)².
Thus the sum will be x² + (x+44)²² = 8080
x² + x² + 88x + 1936= 8080 Combining the right terms
2x² + 8x - 6144 = 0 dividing by 2
x² + 44x - 3072 =0 solving for x
x = 37.6 or -81.6
Therefore, the positive number is 37.6
When you divide fractions, you change each to its reciprocal, then you look multiply them. Using reciprocals helps you easily solve the problem.
The linear speed of the object is the ratio between the measure of the arc it had traveled and the time. For the length of the arc,
2π x (20 m) x (0.2 rad/ 2π rad) = 4 meters
Divide this by the time, 10 s. Thus, the linear speed is equal to 0.4 m/s.
Answer and Step-by-step explanation:
You got everything correct so far except for #4.
4. Yes, it is 1. But it would be in months.
So you would put:
1 month = x
12 months = 1 year.
Since the population increases by 1.5 times a <em>month.</em>
For question number 3.
The equation should be:
<- Function
<- Function when x is 12 months (1 year)
(Put those both the same way I put it.)
It gives you the equation to work with, you just have to plug in the values.
1.5 is in the parenthesis because it needs to be the one that is raised by an exponent.
100 is the initial population, so it stays on the outside.
x is the exponent
