Answer:
The answer is below
Step-by-step explanation:
We need to prove that:
(Root of Sec A - 1 / Root of Sec A + 1) + (Root of Sec A + 1 / Root of Sec A - 1) = 2 cosec A.
Firstly, 1 / cos A = sec A, 1 / sin A = cosec A and tanA = sinA / cosA.
Also, 1 + tan²A = sec²A; sec²A - 1 = tan²A
Answer:
936 jars of peanut butter contain less peanut butter than usual.
Step-by-step explanation:
1. First, we need to find how many jars of peanut butter that contain less peanut butter than advertised are produced every hour.
The factory produces 1200 jars of peanut butter every hour
3.25% of those jars have less peanut butter than advertised
So: multiply (the decimal form of the percent) to find the amount of peanut butter jars that contain less peanut butter than advertised.
So the factory produces 39 jars of peanut butter that contain less peanut butter than advertised.
2. Second, we need to find how many jars of peanut butter that contain less peanut butter than advertised in three 8 hour work days.
Lets add these work days together to find the total amount of hours:
So: three 8 hour work days totals to 24 hours
Since the factory produces 39 jars of peanut butter that contain less peanut butter than advertised per hour. Multiply to find the total amount of jars produced in three 8 hour work days.
A total of 936 peanut butter jars are produced in three 8 hour work days that contain less peanut butter than advertised.
3. If you want to double check your work do the following.
Since the factory produces 1200 jars an hour and 24 hours total three 8 hour work days. Multiply
So there is a total of 28800 jars produced in three 8 hour work days.
Then you can multiply 28800 by 3.25% of jars that contain less peanut butter to find the total amount of peanut butter jars that contain less peanut butter in three 8 hour work days.