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kakasveta [241]
2 years ago
15

3x(2x-7y)-8x(x+2y)+2y(4x-y)

Mathematics
2 answers:
pickupchik [31]2 years ago
6 0

Answer: you're correct.

Brainliest or a thank you please :)) <3

dusya [7]2 years ago
3 0

Answer:

It is -2 x^2 -13xy- 16ux - 2y^2

Step-by-step explanation:

Hope this helps :)

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A shipping company places circular labels on all of their products. Each label measures a 4 inch radius. If the company order 10
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Answer:502.4 Square inches are need.

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In the given figure x = 145º. What theorem can be used to prove the lines p and a
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4 0
3 years ago
Read 2 more answers
What is -0.3 as a fraction? NEED ANSWER NOW
jok3333 [9.3K]

Your answer would be - 3/10

6 0
3 years ago
I need help ASAP! Can anyone please check my work?
STALIN [3.7K]

A = event the person got the class they wanted

B = event the person is on the honor roll

P(A) = (number who got the class they wanted)/(number total)

P(A) = 379/500

P(A) = 0.758

There's a 75.8% chance someone will get the class they want

Let's see if being on the honor roll changes the probability we just found

So we want to compute P(A | B). If it is equal to P(A), then being on the honor roll does not change P(A).

---------------

A and B = someone got the class they want and they're on the honor roll

P(A and B) = 64/500

P(A and B) = 0.128

P(B) = 144/500

P(B) = 0.288

P(A | B) = P(A and B)/P(B)

P(A | B) = 0.128/0.288

P(A | B) = 0.44 approximately

This is what you have shown in your steps. This means if we know the person is on the honor roll, then they have a 44% chance of getting the class they want.

Those on the honor roll are at a disadvantage to getting their requested class. Perhaps the thinking is that the honor roll students can handle harder or less popular teachers.

Regardless of motivations, being on the honor roll changes the probability of getting the class you want. So Alex is correct in thinking the honor roll students have a disadvantage. Everything would be fair if P(A | B) = P(A) showing that events A and B are independent. That is not the case here so the events are linked somehow.

8 0
3 years ago
I can’t figure out the solution I think it is y &lt; -10
Olenka [21]

Hey there!

  • <em>With negatives (-) you have to switch your symbol to the other way</em>
  • \bold{\frac{y}{-2}\leq5}
  • Firstly, substitute the \bold{y\ value  } as an invisible 1
  • So, now we have to flip the equation around
  • \bold{\frac{-1}{2}y\leq5}
  • We have to \bold{multiply} by \bold{-2} on each of your sides
  • \bold{-2\times\frac{-1}{2}\leq-2\times5}
  • \bold{Cancel \ out:2\times\frac{-1}{2}y \ because \ it \ equal \ 1}
  • \bold{Keep: -2\times5 \ because \ it \ helps \ us \ find \ our \ answer}
  • \bold{-2\times5=-10}
  • \boxed{\boxed{\bold{Answer:y\geq-10}}}\checkmark

Good luck on your assignment  and enjoy your day!

~\frak{LoveYourselfFirst:)}

<em />

4 0
3 years ago
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