Answer:
x = -3.5 or -1
Step-by-step explanation:
Add 7 and factor.
2x^2 +9x +7 = 0
(2x +7)(x +1) = 0
x = -3.5 or x = -1 . . . . . values that make the factors zero
_____
<em>Comment on factoring</em>
Factoring ax^2 +bx +c = 0 requires you find factors of ac that have a sum of b. Here, you're looking for factors of 2·7 = 14 that have a sum of 9. If you're observant, you realize that 2+7=9, so 2 and 7 are the factors you want.
Now, you can write the factored form as ...
(ax +p)(ax +q)/a = 0 . . . . where p and q are the factors of ac we just found
The divisor "a" is used to simplify one or both of the factors. Here, we have ...
(2x +2)(2x +7)/2 = 0
(x +1)(2x +7) = 0 . . . . . . we removed a factor of 2 from the first binomial
5/7 that’s that’s the answer
Answer:
- c(n) = 320·0.96^n
- 28 years
Step-by-step explanation:
Each year, the class size is multiplied by 1 - 4% = 96% = 0.96. After n years, it has been multiplied by that number n times. Repeated multiplication is signified using an exponent.
Class size (c) can be modeled by ...
c(n) = 320·0.96^n
__
You want to find n such that c(n) = 100. Put in that value and solve.
100 = 320·0.96^n
100/320 = 0.96^n . . . . . . . divide by 320
log(100/320) = n·log(0.96) . . . . . . . take logs
log(100/320)/log(0.96) = n ≈ 28.4932
In about 28 years, the class will have 100 students.
You did not Include the statements.
Answer:
hi sadly I can't find the proper answer for you, tried working it out
