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Hatshy [7]
3 years ago
9

(1 point) Rewrite the following using a single exponent.

Mathematics
1 answer:
Schach [20]3 years ago
7 0

we are given

\frac{6^a6^a}{36^b} =36^x

now, we can use property of exponent

m^p *m^p=(m)^{2p}

so, we can write as

6^a *6^a=(6)^{a+a}

6^a *6^a=6^{2a}

6^a *6^a=(6^{2})^a

6^a *6^a=(36)^a

now, we can plug back

\frac{36^a}{36^b} =36^x

we can use property of exponent as

\frac{w^m}{w^n} =w^{m-n}

we can write as

36^{a-b} =36^x

now, we can compare both sides exponents

and we will get

x =a-b................Answer

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I need 4 points to graph
Svetach [21]
Let x be 1, y=-12
let x be 2, y=-36
let x be 0, y=-4
let x be 3, y =-108
let x be -1, y=-4/3
let x be -2,y=-4/9
7 0
3 years ago
The lifetime of two light bulbs are modeled as independent and exponential random variables X and Y, with parameters lambda and
Scorpion4ik [409]

Answer:

\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)

Step-by-step explanation:

The PDF of X is

\bf f(x)=\lambda e^{-\lambda x}\;(x\geq0)

The PDF of Y is

\bf g(x)=\mu e^{-\mu x}\;(x\geq0)

The means of X and Y are respectively,

\bf \displaystyle\frac{1}{\lambda}\;,\displaystyle\frac{1}{\mu}

so we can see that the larger the parameter, the smaller the mean. Hence the PDF of Z = min(X, Y) is an exponential with the largest parameter of the two.

Therefore, the PDF of Z is

\bf h(x)=max(\lambda,\mu) e^{-max(\lambda,\mu) x}\;(x\geq0)

7 0
3 years ago
The point slope form of a line that has a slope of -2 and passes through point (5,-2) is shown below.
Likurg_2 [28]
Insert the point, (5,-2) with the slope of the line to figure out the equation. You can either use point-slope form, or plug it for for slope-intercept form.

Slope-intercept form:
-2 = -2(5) + b
-2 = -10 + b
Add 10 on both sides
8 = b

Thus,

y = -2x + 8

Answer is B
4 0
3 years ago
Justin is 2 years older than one third Marcella’s age. Aimee is 5 years younger than 2 times Justin’s age. Define a variable and
KIM [24]

Answer:

Step-by-step explanation:

J = (1/3)M + 2 <=== ur expression would be : (1/3)M + 2

A = 2J - 5

if marcella is 63....

J = (1/3 * 63) + 2                              A = 2J - 5

J = 63/3 + 2                                    A = 2(23) - 5

J = 21 + 2                                        A = 46 - 5

J = 23 <== justin's age                   A = 41 <=== Aimee's age

4 0
3 years ago
The average of Aaron's three test scores must be at least 93 to earn an A in the class. Aaron scored 89 on the first
victus00 [196]

Answer:

Aaron must obtain a 96 or higher to achieve the desired score to earn an A in the class.

Step-by-step explanation:

Given that the average of Aaron's three test scores must be at least 93 to earn an A in the class, and Aaron scored 89 on the first test and 94 on the second test, to determine what scores can Aaron get on his third test to guarantee an A in the class, knowing that the highest possible score is 100, the following inequality must be written:

93 x 3 = 279

89 + 94 + S = 279

S = 279 - 89 - 94

S = 96

Thus, at a minimum, Aaron must obtain a 96 to achieve the desired score to earn an A in the class.

4 0
3 years ago
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