Correct answer is E. The primary purpose of Passage 1 is to Highlight a concern.
The passage talks about spam and junk mail in our mail inbox and one has to go through it all to find out real and important mails. This spam mails and the manner they flood our mails in is concerning. This is what the passage highlights. Thus E is the best answer.
While junk mail often comes from opt-in services, such as from businesses, spam refers to messages that the user did not opt to receive. When you're crafting a mailing list or sending out an advertisement, it's important that your message not come off as spam.
To learn more about spam and junk mail from given link
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The total cost of the dinner is $176.20.
<h3>What is the total cost of the dinner?</h3>
The total cost of the dinner is the sum of the bill for the dinner, the tax and the tip.
Total cost = tip + bill of the dinner + tip
Tax = 0.08 x 140 = $11.20
Total cost = $140 + $25 + $11.20 = $176.20
To learn more about taxes, please check: brainly.com/question/25311567
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Answer:
<u>From the box plot we get:</u>
- Minimum - 14
- Maximum - 88
- Quartile 1 - 34
- Quartile 3 - 65
- Median - 48
Answer:
S=32 D=34
Step-by-step explanation:
{-----------------VARIABLES------------}
D=Drake
S=Stephanie
TA=Total Age
{----------------GIVEN/EQUATIONS-------------}
D=S+2
TA=D+2s
{--------------SUB/SOLVE---------------}
98=D+2S
SUB FOR D
98=3S+2
96=3S
S=32
D=S+2
D=34
Answer:
a)120
b)6.67%
Step-by-step explanation:
Given:
No. of digits given= 6
Digits given= 1,2,3,5,8,9
Number to be formed should be 3-digits, as we have to choose 3 digits from given 6-digits so the no. of combinations will be
6P3= 6!/3!
= 6*5*4*3*2*1/3*2*1
=6*5*4
=120
Now finding the probability that both the first digit and the last digit of the three-digit number are even numbers:
As the first and last digits can only be even
then the form of number can be
a)2n8 or
b)8n2
where n can be 1,3,5 or 9
4*2=8
so there can be 8 three-digit numbers with both the first digit and the last digit even numbers
And probability = 8/120
= 0.0667
=6.67%
The probability that both the first digit and the last digit of the three-digit number are even numbers is 6.67% !
