Find the range and the interquartile range of the given data set. 2, 4, 7, 8, 16, 19, 21

Please answer the circled questions below!

Anton [14]

Answer:

Step-by-step explanation:

1. The y-values in the table are constant, so the slope is 0. It is a horizontal line.

There is no x-intercept.

The y-intercept is (0, 1).

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For lines in standard form, the intercepts can be found easily. The x-intercept is the value of x when y=0:

ax +0 = c

x = c/a . . . . x-intercept

Similarly, the y-intercept is the value of y when x=0:

0 +by = c

y = c/b

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3. x-intercept = (-20/2, 0) = (-10, 0)

y-intercept = (0, -20/-5) = (0, 4)

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4. x-intercept = (-6/1, 0) = (-6, 0)

y-intercept = (0, -6/-3) = (0, 2)

Plot these points and draw a line through them.

8 0

3 years ago

A machine for baking hay produces cylindrical bales that are 6 feet in diameter and 5 1/3 feet in height. Which is closest to th

GaryK [48]

We know that
diameter=6 ft----------> r=6/2------> r=3 ft
h=5 1/3 ft------> (5*3+1)/3-----> 16/3 ft
[volume of a cylindrical bales]=pi*r²*h----> pi*3²*16/3---> 150.72 cm³

the answer is the option
B 151 cm³

5 0

3 years ago

A model rocket is launched with an initial velocity of 200 ft per second. The height h, in feet, of the rocket t seconds after t

Solnce55 [7]

Answer:

2.10 s, 10.40 s.

Step-by-step explanation:

We know that the height of the rocket is given by the function:

$h=-16t^2+200t$

We are asked to find the time for which the height of the rocket will be 350 ft. So, for that moment, we know the height but we don't know the time; however, we know that the equation can help us to find the time, doing h=350:

$350=-16t^2+200t$

The last is a quadratic equation, which can be put in the form $at^2+bt+c=0$ and solved applying the formula:

$t=\frac{-b+-\sqrt{b^2-4ac} }{2a}$

So, let's put the equation on the form $at^2+bt+c=0$ adding $16t^2$ and subtracting $200t$ to each side of the equation; the result is:

$16t^2-200t+350=0$

So, we note that a=16, b=-200, and c=350.

Then,

$t_1=\frac{200-\sqrt{200^2-4*16*350} }{2*16}=2.10$

$t_2=\frac{200+\sqrt{200^2-4*16*350} }{2*16}=10.40$

According to the equation, that are the times for which the height will be 350 ft; that is because the rocket is going to ascend and then to fail again to the ground.

4 0

3 years ago

How many 1 2/3 cup servings are in 15 1/4 cups of salsa

lilavasa [31]

Answer:

9.18

Step-by-step explanation:

1.66/15.25=9.18

6 0

3 years ago

Can someone please help me?

bulgar [2K]

Solution:

Given:

18 = 2b

Solve the equation by isolating the variable.

=> 18 = 2b
=> 2b/2 = 18/2
=> b = 9

The value of b is 9.

Hoped this helped!

6 0

2 years ago