4 years ago

How can i solve this equation?

1 answer:

german4 years ago

7 0

Factorizing sin2x+3sinx+2=0

sin^2 x+2sinx+sinx+2=0

or sinx(sinx+2)+1(sinx+2)=0

or (sinx+1)(sinx+2)=0

Now as sinx+2≠0, we have sinx+1=0

or sinx= −1 =sin(3π/2)

Hence, x=2nπ+3π/2

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$- 6h + 4 - 3 + h = 11$
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4 years ago

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________________

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3 years ago

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1. f = g(m1 - m2)/d2

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