Answer:
FOR red one = 1/26
FOR black three = 1/26
FOR six of hearts = 1/52
Step-by-step explanation:
TECHNICALLY EVERY CARD WOULD BE 1/52 BUT SINCE THERE R TWO DIFFERENT TYPES OF BLACKS AND REDS THE FIRST TWO ARE 1/26
HOPE I HELPED
PLS MARK BRAINLIEST
DESPERATELY TRYING TO LEVEL UP
✌ -ZYLYNN JADE ARDENNE
JUST A RANDOM GIRL WANTING TO HELP PEOPLE!
PEACE!
Let x=papers on Saturday and y=papers on Sunday
First make equations for the information given to you
x+y=52 (total papers) and y= x+8 (he sold 8 more on Sunday)
then since you know y=x+8 then substitute it in the other equation like so
x+(x+8)=52 which means 2x+8=52 which means 2x=44 and therefore x=22
the problem however asks for sunday and not saturday, so solve for y now
y=x+8 which means y=22+8 which means y=30
He sold 30 papers on Sunday
There are 120 ways in which 5 riders and 5 horses can be arranged.
We have,
5 riders and 5 horses,
Now,
We know that,
Now,
Using the arrangement formula of Permutation,
i.e.
The total number of ways
,
So,
For n = 5,
And,
r = 5
As we have,
n = r,
So,
Now,
Using the above-mentioned formula of arrangement,
i.e.
The total number of ways
,
Now,
Substituting values,
We get,

We get,
The total number of ways of arrangement = 5! = 5 × 4 × 3 × 2 × 1 = 120,
So,
There are 120 ways to arrange horses for riders.
Hence we can say that there are 120 ways in which 5 riders and 5 horses can be arranged.
Learn more about arrangements here
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The choice D is in scientific notation
7.8*10^5