Answer:
Step-by-step explanation:
Given equation is,
x² + (p + 1)x = 5 - 2p
x² + (p + 1)x - (5 - 2p) = 0
x² + (p + 1)x + (2p - 5) = 0
Properties for the roots of a quadratic equation,
1). Quadratic equation will have two real roots, discriminant will be greater than zero. [(b² - 4ac) > 0]
2). If the equation has exactly one root, discriminant will be zero [(b² - 4ac) = 0]
3). If equation has imaginary roots, discriminant will be less than zero [(b² - 4ac) < 0].
Discriminant of the given equation = 
For real roots,

p² + 2p + 1 - 8p + 20 > 0
p² - 6p + 21 > 0
For all real values of 'p', given equation will be greater than zero.
Answer:
B - y = 2x - 8
Step-by-step explanation:
Step 1: find slope
2x + 4y = 6
4y = -2x + 6
Make y the subject of the formula
y =( -2x + 6)/4
We can separate to get the slope
y = -2x/4 + 6/4
y = -x/2 + 3/2
Slope m = -1/2
Step 2: using a point slope form equation
y - y1 = m ( x - x1)
Note: if two lines are perpendicular to the other, it is always a negative reciprocal of each other
ie m = 2
Substitute m into the equation
y - y1 = 2(x - x1)
Step 3: sub the point
( 6 , 4)
x1 = 6
y1 = 4
y - 4 = 2( x - 6)
Step 4 : using a slope intercept form equation
Open the bracket
y - 4 = 2x - 12
y = 2x - 12 + 4
y = 2x - 8
The equation of a line is
y = 2x - 8
Answer:
The area of the triangle is of 8 units of area.
Step-by-step explanation:
Answer:
The area of the triangle is of 21 units of area.
Step-by-step explanation:
The area of a triangle with three vertices
is given by the determinant of the following matrix:

In this question:
Vertices (1,0) (5,0) (3,4). So




The area of the triangle is of 8 units of area.
Answer:
1. Sides 1 and 2 are congruent so sides 3 are also congruent
2. Since angles D and R are the same and the two sides are the same, the triangles are the same
For this case what we must do is find a quadratic function that is already factored.
This is because in the factored quadratic equations, it is easier to observe the zeros of the function.
In this case, the zeros of the function represent the time at which the company did not make any profit.
We have the following equation:
p (t) = 40 (t - 3) (t + 2) (t - 5) (t + 3)
We observed that there was no gain in:
t = 3
t = 5
The other roots are discarded because they are negative
Answer:
a.p (t) = 40 (t - 3) (t + 2) (t - 5) (t + 3)