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nadya68 [22]
2 years ago
8

13. The photo below is being enlarged to form a 24-by 30-inch print. What is the scale factor being used to enlarge it?​

Mathematics
1 answer:
RUDIKE [14]2 years ago
5 0

Answer:

6

Step-by-step explanation:

24/4 = 6

30/5 = 6

Dividing the values of the larger print by the corresponding values of the smaller print results in a scale factor of 6

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The table shows the results of a survey of 400 random people on whether they like liquid soap, bar soap, or both. A 4-column tab
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<u>Step-by-step explanation:</u>

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3 years ago
A. 4,-4<br> B. 2,-5<br> C.0,6<br> D.-2,5<br> Which would it be?
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Answer:

A

Step-by-step explanation:

If we insert the original coordinates into the problem, we will find the answer.

(2+2, 1-5)

so, once solved

(4, -4)

remember, adding to X means moving the point right, subtracting to X means moving left.

Adding to Y means moving the point up, subtracting to Y means moving down.

6 0
2 years ago
A website manager has noticed that during the evening​ hours, about 5 people per minute check out from their shopping cart and m
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Answer:

a) Poisson distribution

b) 99.33% probability that in any one minute at least one purchase is​ made

c) 0.05% probability that seven people make a purchase in the next four ​minutes

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

In which

x is the number of sucesses

e = 2.71828 is the Euler number

\mu is the mean in the given time interval.

5 people per minute check out from their shopping cart and make an online purchase.

This means that \mu = 5

a) What model might you suggest to model the number of purchases per​ minute? ​

The only information that we have is the mean number of an event(purchases) in a time interval. Each event is also independent fro each other. So you should suggest the Poisson distribution to model the number of purchases per​ minute.

b) What is the probability that in any one minute at least one purchase is​ made? ​

Either no purchases are made, or at least one is. The sum of the probabilities of these events is 1. So

P(X = 0) + P(X \geq 1) = 1

We want to find P(X \geq 1)

So

P(X \geq 1) = 1 - P(X = 0)

In which

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-5}*(5)^{0}}{(0)!} = 0.0067

1 - 0.0067 = 0.9933.

99.33% probability that in any one minute at least one purchase is​ made

c) What is the probability that seven people make a purchase in the next four ​minutes?

The mean is 5 purchases in a minute. So, for 4 minutes

\mu = 4*5 = 20

We have to find P(X = 7).

P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}

P(X = 0) = \frac{e^{-20}*(20)^{7}}{(7)!} = 0.0005

0.05% probability that seven people make a purchase in the next four ​minutes

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Answer:

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Step-by-step explanation:

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3 years ago
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