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vaieri [72.5K]
3 years ago
6

What are the first four terms of the sequence defined recursively below

Mathematics
2 answers:
Effectus [21]3 years ago
4 0
At n = 2
a₂ = (-1)² + 3a₂₋₁ + 2
a₂ = 1 + 3a₁ + 2
a₂ = 1 + (3)(5) + 2
a₂ = 18

At n = 3
a₃ = (-1)³ + 3a₃₋₁ + 2
a₃ = -1 + 3a₂ + 2
a₃ = -1 + (3)(18) + 2
a₃ = 55

At n = 4
a₄ = (-1)⁴ + 3a₄₋₁ + 2
a₄ = 1 + 3a₃ + 2
a₄ = 1 + (3)(55) + 2
a₄ = 168

The first four terms are 5, 18, 55, 168




NikAS [45]3 years ago
4 0

Answer:

The first four terms are 5, 18, 55, 168

Step-by-step explanation:

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