Question

-12u+3=8v+1 helppppp me out wit this

Answer 1

You want g (u), so we have to solve this equation for v.

$8v+1=-12u+3\qquad\text{subtract 1 from both sides}\\\\8v=-12u+2\qquad\text{divide both sides by 8}\\\\v=\dfrac{2-12u}{8}\\\\v=\dfrac{2:2-12u:2}{8:2}\\\\v=\dfrac{1-6u}{4}\\\\v=\dfrac{1}{4}-\dfrac{6}{4}u\\\\v=\dfrac{1}{4}-\dfrac{6:2}{4:2}u\\\\v=\dfrac{1}{4}-\dfrac{3}{2}u\\\\Answer:\ \boxed{g(u)=\dfrac{1}{4}-\dfrac{3}{2}u}$

Answer 2

Subtract 3 from both sides

-12u = 8v + 1 - 3

Simplify 8v + 1 - 3 to 8v - 2

-12u = 8v - 2

Divide both sides by -12

u = - 8v - 2/12

Factor out the common term 2

u = - 2(4v - 1)/12

Simplify 2(4v - 1)/12 to 4v - 1/6

u = - 4v - 1/6