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True [87]
3 years ago
11

Help me pleeeeeeeeeaze

Mathematics
1 answer:
kobusy [5.1K]3 years ago
5 0

a(x+3) < 5x+15-x\\\\ax+3a < 5x+15-x\\\\ax+3a < 4x+15\ \ \ |-3a\\\\ax < 4x+15-3a\ \ \ \ |-4x\\\\ax-4x < 15-3a\\\\(a-4)x < 15-3a\\\\\text{The solution is all real numbers if}\ a-4=0\ \ \ |+4\\\\\boxed{a=4}\\\\\text{Check:}\\\\4(x+3) < 5x+15-x\\4x+12 < 4x+15\ \ \ \ |-4x\\12 < 15\ TRUE\to x\in\mathbb{R}

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For some postive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770. The value of Z is
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Answer:

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Step-by-step explanation:

Given that;

For some positive value of Z, the probability that a standardized normal variable is between 0 and Z is 0.3770.

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P(Z < z)-P(Z < 0) = 0.3770

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SO to determine the value of z for which it is equal to 0.877, we look at the

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therefore, P(Z ≤ 1.16 ) = 0.877

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3 years ago
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