What is the interquartile range of the following data set? 45,12,48,96,61,84,29,1,72,5,14
slava [35]
Answer:
60
Step-by-step explanation:
Population size : 11
To calculate inter-quartile range
- Order the data from least to greatest.
- Calculate the median of both the lower and upper half of the data.
- The IQR is the difference between the upper and lower medians.
Step 1
1, 5 , 12 ,14 , 29 , 45 , 48, 61 , 72 , 84 , 96
Step 2
medium = 45
Step 3
Q1
1 , 5 , 12 ,14 , 29
median = 12
Q3
48 , 61 , 72 , 84 , 96
median = 72
Step 4
IQ = Q3 - Q1
= 72 - 12
= 60
Step-by-step explanation:
If he can walk 14 miles in 5 hours, take 14÷5 to find out how long he can walk in 1 hour. (2.8)
Then take 2.8 miles times 3.5 hours is 9.8 miles
Answer:
y = 1.2x - 3 (slope intercept form)
or
5y-6x = -15 (standard form)
Step-by-step explanation:
Two parallel lines have the same slope, which means that our line's slope, will also be 1.2.
we can use the formula to find the equation of the line:
y-y1 = m (x-x1)
y1 - y coordinate of a point on the line
x1 - x coordinate of the same point on the line
m - slope
and we get:
y+3 = 1.2 (x-0)
y = 1.2x - 3 (slope intercept form)
or
5y-6x = -15 (standard form)
Answer:
The average cost per vet visit was $19.25.
Step-by-step explanation:
From the information given, you can find the average cost per visit by dividing the total amount paid for a year's worth of vet visits by the number of visits:
269.50/14= $19.25
According to this, the answer is that the average cost per vet visit was $19.25.
Step-by-step explanation:
ATQ,
Let d be the number of kilograms of dark chocolate she buys and m be the number of kilograms of milk chocolate she buys.
She needs to buy 120 kg of chocolate in total for her next order, and her recipe calls for twice the amount of dark chocolate as milk chocolate.
So,
m = 2d .....(1)
m + d = 120 ...(2)
We can also solve the above equations,
Put m = 2d in equation (2)
2d + d = 120
3d=120
d = 40
Put d = 40 in equation (1)
m = 2(40)
m = 80
Hence, she will need 40 kg of dark chocolate and 80 kg of milk chocolate.
