Considering the perimeter of the rectangle, we have that the length is of 9 inches and the width is of 55 inches.
<h3>What is the perimeter of a rectangle?</h3>
The perimeter of a rectangle of length l and width w is given as follows:
P = 2(l + w).
The length is an odd integer and the width is <u>5 times the next consecutive odd integer,</u> hence:
l = x, w = 5(x + 2).
The perimeter is of 128 inches, hence:
128 = 2l + 2w
128 = 2x + 10(x + 2)
128 = 2x + 10x + 20
12x = 108
x = 9.
Hence the length is of 9 inches and the width is of 55 inches.
More can be learned about the perimeter of a rectangle at brainly.com/question/10489198
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Answer:
Step-by-step explanation:
Answer:
Surface area of sphere = 4πr²
r = radius
radius = diameter /2
= 12/2
= 6units
Surface area = 4π×6²
= 144π
= 452.4 square units
Hope this helps.
Answer:
a = 2/3
Step-by-step explanation:
(4(x+1) + 20 )/(x+1) = 16
4x + 4 + 20 = 16x + 16
12x = 8
x = 2/3
Answer:
the required slope of the points is -1...