First, we need to know how much the car depreciates each year. Multiply the price of the car by the percentage.
We can turn 9% into a decimal by moving the decimal point two places to the right.
9% = .09
24500 * .09 = 2205
Multiply the product by the amount of years you want to predict the price at.
2205 * 10 = 22050
Subtract that from the original price of the car.
24500 - 22050 = 2450
The value of a 10 year old car that costs $24500 and depreciates 9% every year will cost $2450.
I think what you meant was
(2x - 5)² = 11 -- (1)
Square root both sides of (1), i.e.
√(2x - 5)² = ± √11 -- (2)
From (2), we have
2x - 5 = ± √11 -- (3)
By adding 5 to both sides in (3), we have
2x = 5 ± √11 -- (4)
Divide both sides of (4) by 2, and we obtain
x = (5 ± √11)/2 -- (5)
From (5), the solution set of (1) is
x = (5 + √11)/2, (5 - √11)/2 ...Ans.
8.57 for the first one and, I’m not sure a bout the second time though
The picture in the attached figure
we know that
RX+RA+XA=24
XA=24-RA-RX------> XA=24-11-4----> XA=9
XA=XP+PA
so
XP+PA=9------> XP=9-PA-----> equation 1
RX/XP=RA/PA
11*XP=4*PA-----> equation 2
substitute equation 1 in equation 2
11*[9-PA]=4*PA-----> 99-11*PA=4*PA----> 15*PA=99----> PA=99/15
PA=6.6
XP=9-PA-----> XP=9-6.6----> XP=2.4
the answer is the option<span>
B. XP = 2.4, PA = 6.6 </span>