If r+s/r =3 and t+r/t =5, what is the value of s/t ? (A) 12 (B) 35 (C) 4 (D) 8 (E) 16

How would you solve y+1= -4x ? with a step by step solution

polet [3.4K]

Answer:

There are an infinite number of solutions.

Step-by-step explanation:

An equation with 2 unknowns give an infinite amount of solutions, here is just one of the many:

Let y= 3 ( y can be any number)

(3) + 1 = -4x

4 = -4x

x = -4/4

x= -1

(x;y) = (-1;3)

Generally x and y can be any number, just let x or y be any number, then find the other variable based on the value of the number u assumed.

3 0

3 years ago

WILL MARK BRAINLIEST

ryzh [129]

The graph behavior of the function that satisfied the conditions given are:

Horizontal asymptote at y = 0.

Vertical asymptotes at x = -1 and x = 1.

<h3>What are the asymptotes of a function f(x)?</h3>

The vertical asymptotes are the values of x which are outside the domain, which in a fraction are the zeroes of the denominator, or values of x for which the value of the limit goes to infinity.

The horizontal asymptote is the value of f(x) as x goes to infinity, as long as this value is different of infinity, that is, the limit of f(x) as x goes to infinity.

Hence, for this problem, the graph behavior is given by the following asymptotes:

Horizontal asymptote at y = 0.

Vertical asymptotes at x = -1 and x = 1.

More can be learned about asymptotes at brainly.com/question/16948935

#SPJ1

5 0

2 years ago

A student researcher compares the heights of men and women from the student body of a certain college in order to estimate the d

maria [59]

Answer:

(0.6613, 8.3387)

Step-by-step explanation:

Let the heights of men be the first population and the heights of women be the second population. Then

We have $n_{1} = 15$ , $\bar{x}_{1} = 69.4$ , $s_{1} = 3.09$ and

$n_{2} = 7$ , $\bar{x}_{2} = 64.9$ , $s_{2} = 2.58$ . The pooled

estimate is given by

$s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(15-1)(3.09)^{2}+(7-1)(2.58)^{2}}{15+7-2} = 8.68$

The 99% confidence interval for the true mean difference between the mean height of the men and the mean height of the women is given by (if the samples are independent)

$(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{15}+\frac{1}{7}}$ , i.e.,

$(69.4-64.9)\pm t_{0.005}2.946\sqrt{\frac{1}{15}+\frac{1}{7}}$

where $t_{0.005}$ is the 0.5th quantile of the t distribution with (15+7-2) = 20 degrees of freedom. So

$4.5\pm(-2.845)(2.946)(0.458)$ , i.e.,

(0.6613, 8.3387)

5 0

3 years ago

Solve the following problems. a. 2 ft. 5 in. + 9 in. b. 4 yd. 8 in + 6 yd. 6 in. c. 29 yd. 2 ft. 11 in. + 55 yd. 1 ft. 10 in. +

Arada [10]

a. 2 ft. 5 in. + 9 in.=2 ft 14 in.=2 ft. (12+2) in.=3 ft. 2 in. (since 1 ft.=12 in.);

 b. 4 yd. 8 in + 6 yd. 6 in. =(4+6) yd. (8+6) in.=10 yd. 14 in.=10 yd. (12+2) in.=10 yd. 1 ft. 2 in.;

c. 29 yd. 2 ft. 11 in. + 55 yd. 1 ft. 10 in. + 13 yd. 1 ft. 3 in.=(29+55+13) yd. (2+1+1) ft. (11+10+3) in.=97 yd. 4 ft. 24 in.=97 yd. (3+1) ft. (12+12) in.=98 yd. 3 ft.=99 yd.


d. 4,839 sq. yd. 8 sq. ft. 139 sq. in. + 7 sq. ft. 124 sq. in.=4,839 sq. yd. (8+7) sq. ft. (139+124) sq. in.=4,839 sq. yd. 15 sq. ft. 263 sq. in. =
4,839 sq. yd. 15 sq. ft. (144+119) sq. in.=4,839 sq. yd. 16 sq. ft. 119 sq. in.=4,839 sq. yd. (9+7) sq. ft. 119 sq. in.=4,840 sq. yd. 7 sq. ft. 119 sq. in.

4 0

3 years ago

Niko spent $23.25 a raffle ticket that cost $.75 each which of the following is the number of raffle tickets nickel bought

miskamm [114]

Answer:

31 raffle tickets

Step-by-step explanation:

23.25 divided by 0.75 = 31

8 0

3 years ago

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