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Rzqust [24]
3 years ago
13

How many different 5 digit cominations can you make with the numbers 1-9?

Mathematics
1 answer:
Goryan [66]3 years ago
8 0

Answer: 59049

Step-by-step explanation: To choose the first digit, we have 9 options. As the digit could repeat, for the second, we have 9 options too. Follow this procedure, we have nine options for all digits. Therefore, the result is obtained by multiplying five terms equal to 9, that is 9x9x9x9x9 = 59049.

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Quisssssssss !!!!<br><br>x + 2x + 9y - 7y​
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4 0
2 years ago
Read 2 more answers
A typical cup of coffee contains about 100 mg of caffeine and every hour approximately 16% ofthe amount of caffeine inthe body i
Over [174]

Answer:

a) \frac{dC}{dt} = rC

And for this case we can rewrite the model like this:

\frac{dC}{C} = r dt

If we integrate both sides we got:

ln C = rt + k

If we use exponentials for both sides we got:

C = e^{rt} e^k = C_o e^{rt}

For this case C_o = 100 mg and r = -0.16

So then our model would be given by:

C(t) = 100 e^{-0.16 t}

Where t represent the number of hours

b) C(5) = 100 e^{-0.16*5}= 44.9329

Step-by-step explanation:

Part a

For this case we can assume the proportional model given by:

\frac{dC}{dt} = rC

And for this case we can rewrite the model like this:

\frac{dC}{C} = r dt

If we integrate both sides we got:

ln C = rt + k

If we use exponentials for both sides we got:

C = e^{rt} e^k = C_o e^{rt}

For this case C_o = 100 mg and r = -0.16

So then our model would be given by:

C(t) = 100 e^{-0.16 t}

Where t represent the number of hours

Part b

For this case we can replace the value t=5 into the model and we got:

C(5) = 100 e^{-0.16*5}= 44.9329

7 0
3 years ago
5x5=25 i did the quiz and got it right
Sedaia [141]
Congratsss good jobbb
5 0
2 years ago
Read 2 more answers
Factorise x^2-y^2-2x+6y-8
Talja [164]
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3 0
3 years ago
Let S be the universal set, where: S={1,2,3,...,18,19,20}
just olya [345]

Answer:

A∪B = {1,2,3,4,5,6,7,8,9,11,13,14,15,16,18,20}

A∩B = {1,5,6,7,8,9,11,14,15}

Step-by-step explanation:

A∪B is the elements in A or B. So, for this question, we just need to find the numbers that are in A or B. Remember not to add anything that is not in set A or B and not write the same number twice.

A∩B is the elements in A and B. Therefore, for this question, we just need to find the numbers which appeared in both set A and B.

Hope this helps :)

3 0
3 years ago
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