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3 years ago

Factorise x^2-y^2-2x+6y-8

1 answer:

3 0

X^2 - y^2 - 2x + 6y - 8
= (x^2 - 2x + 1) - (y^2 - 6y + 9) - 8 - 1 + 9 
= (x - 1)^2 - (y - 3)^2 
= [(x - 1) - (y - 3) ] [(x - 1) + (y - 3)] 
= (x - 1 - y + 3) ( x - 1 + y - 3) 
= (x - y + 2) (x + y - 4)

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2 years ago

PLEASE FOR 100 POINTS!!! PLEASE!!!

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3 years ago

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2 years ago

Cherie is jogging around a circular track. She

skelet666 [1.2K]

Answer:

Measure of minor angle JOG is $95.5^{\circ}$

Step-by-step explanation:

Consider a circular track of radius 120 yards. Assume that Cherie starts from point J and runs 200 yards up to point G.

$\therefore m JG = 200 yards, JO=120 yards$ .

Now the measure of minor arc is same as measure of central angle. Therefore minor angle is the central angle $\angle JOG = \theta$ .

To calculate the central angle, use the arc length formula as follows.

$Arc\:Length\left(s\right) = r\:\theta$

Where $\theta$ is measured in radian.

Substituting the value,

$200=120\:\theta$

Dividing both side by 120,

$\dfrac{200}{120}=\theta$

Reducing the fraction into lowest form by dividing numerator and denominator by 40.

$\therefore \dfrac{5}{3}=\theta$

Therefore value of central angle is $\angle JOG = \theta=\left(\dfrac{5}{3}\right)^{c}$ , since angle is in radian

Now convert radian into degree by using following formula,

$1^{c}=\left(\dfrac{180}{\pi}\right)^{\circ}$

So multiplying $\theta$ with $\left(\dfrac{180}{\pi}\right)^{\circ}$ to convert it into degree.

$\left(\dfrac{5}{3}\right)^{c}=\left(\dfrac{5}{3}\right) \times \left(\dfrac{180}{\pi}\right)^{\circ}$

Simplifying,

$\therefore \theta = 95.49^{circ}$

So to nearest tenth, $\angle JOG=95.5^{circ}$

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3 years ago