Factorise x^2-y^2-2x+6y-8

1 answer:

3 0

X^2 - y^2 - 2x + 6y - 8
= (x^2 - 2x + 1) - (y^2 - 6y + 9) - 8 - 1 + 9 
= (x - 1)^2 - (y - 3)^2 
= [(x - 1) - (y - 3) ] [(x - 1) + (y - 3)] 
= (x - 1 - y + 3) ( x - 1 + y - 3) 
= (x - y + 2) (x + y - 4)

You might be interested in

PLZZ HELP

kupik [55]

Answer:

A) (-2,0) and (6,0)

B) (0,-12)

C) (2,-16)

Step-by-step explanation:

In the graph you see below, you can tell that the two x intercepts are at (-2,0) and (6,0), while the y intercept is at (0,-12). You can also see that the vertex is at (2,-16). Hope this helps!

6 0

3 years ago

If the Quadratic functions for the equations are graphed, which is the widest?

Amanda [17]

y = ax^2

If the absolute value of a is <1 the graph is wider than when a = 1

If the absolute value of a is >1 the graph is narrow than when a = 1

The only function that fits that description is

y = 2x^2

7 0

3 years ago

According to cbs money watch, the average monthly household cellular phone bill is $100. suppose monthly household cell phone bi

iren2701 [21]

The probability that a randomly selected monthly cell phone bill is more than $127 is given by

$P(X\ \textgreater \ 127)=1-P(X\ \textless \ 127) \\ \\ =1-P\left(z\ \textless \ \frac{127-100}{11.35} \right)=1-P(z\ \textless \ 2.38) \\ \\ =1-0.99132=0.00868$