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Valentin [98]
3 years ago
5

ANSWER ME PLZ THANKS

Mathematics
1 answer:
nignag [31]3 years ago
6 0

Answer:

b

Step-by-step explanation:

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If y varies directly as x and inversely as z and y = 4 when x = 2 and z = 7, find y when x =
S_A_V [24]

Answer:

y = 28

Step-by-step explanation:

Given that y varies directly as x and inversely as z then the equation relating them is

y = \frac{kx}{z} ← k is the constant of variation

To find k use the condition y = 4 when x = 2 and z = 7, then

4 = \frac{2k}{7} ( multiply both sides by 7 )

28 = 2k ( divide both sides by 2 )

14 = k

y = \frac{14x}{z} ← equation of variation

When x = 6 and z = 3 , then

y = \frac{14(6)}{3} = 14 × 2 = 28

4 0
3 years ago
2. The table shows distance, y, that Mario runs in x minutes.
Zepler [3.9K]
Assuming the left is minutes and the right is distance, Mario runs 1 mile in 7 minutes
(a) y=x/7
(b) the rate of change is 7
(c) if he ran for 70 minutes then his distance is 10 miles.
*for (c) just plug in the number given. Replace it with x and divide it by 7.*
7 0
2 years ago
List angles in order from smallest to largest
shepuryov [24]
Answer:

∠S, ∠R, ∠T

Step-by-step explanation:

4 0
2 years ago
Cgi- jici- oir<br><br>only show type person come​
Feliz [49]

Answer:

what

Step-by-step explanation:

8 0
2 years ago
Select the sentence that represents the equation below.
Alexeev081 [22]

Answer:

Eight less than four times a number is equal to two times the difference of double that same number decreased by three.

Step-by-step explanation:

The given equation is:

4x−8=2(2x−3)

We will try to translate the given equation in English.

We can see that the variable used is only one. On the left hand side of the equation 8 is being subtracted from 4 times of the variable and on the right hand side 3 is being subtracted from 2 times of variable and then being multiplied by two.

From the given option, correct answer is:

Eight less than four times a number is equal to two times the difference of double that same number decreased by three.

5 0
3 years ago
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