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xxTIMURxx [149]
3 years ago
10

I don’t understand this question please help

Mathematics
1 answer:
lisov135 [29]3 years ago
8 0

Answer:

Between 3² and 4⁴

Between 3 and 4

Step-by-step explanation:

Number 15 is between between 3² and 4⁴

While √15 = 3.8 72 is between 3 and 4.

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Natasha drives at a speed of 80 miles per hour.<br> How long will it take to drive 440 miles?
Alex777 [14]

Answer:

5.5 hours

Step-by-step explanation:

6 0
3 years ago
How much longer is the side of a cube with a surface area of 1,200 square inches than a cube with the surface area of 768 square
saul85 [17]

Answer:

2.83 inches longer

Step-by-step explanation:

The SA of a cube is 6s^2.

Therefore the length of the side of the 1200 square inches cube is approximately 14.142 inches long.

The length of the side of the 768 square inches cube is approximately 11.314 inches long.

If you subtract those two numbers, you get the difference in the lengths which is approximately 2.83 inches.

8 0
3 years ago
Solve the inequality 2(x-6)&lt;1/2 (12x-8) neeed help
Rudiy27
Hi there...

2( x - 6) < 1/2(12x - 8)
2x - 12 < (12x- 8)/2
2x - 12 < 6x - 4
2x - 6x < -4 + 12
-4x < 8
Divide both sides by -4
-4x/-4 < 8/-4
x > - 2 
5 0
3 years ago
A drinks factory packed their drinks into red and yellow boxes. There were 24 more red boxes than yellow boxes. Each red box con
ira [324]

Answer:

A) 128

B) 7800

Step-by-step explanation:

Trial and error until I got to 75 x 104 and 60 x 128 (which abides by the fact that there has to be 24 more red boxes) which equals 7800 and 7680 and if you take them away from each other you get 120

3 0
3 years ago
Using the Breadth-First Search Algorithm, determine the minimum number of edges that it would require to reach
jekas [21]

Answer:

The algorithm is given below.

#include <iostream>

#include <vector>

#include <utility>

#include <algorithm>

using namespace std;

const int MAX = 1e4 + 5;

int id[MAX], nodes, edges;

pair <long long, pair<int, int> > p[MAX];

void initialize()

{

   for(int i = 0;i < MAX;++i)

       id[i] = i;

}

int root(int x)

{

   while(id[x] != x)

   {

       id[x] = id[id[x]];

       x = id[x];

   }

   return x;

}

void union1(int x, int y)

{

   int p = root(x);

   int q = root(y);

   id[p] = id[q];

}

long long kruskal(pair<long long, pair<int, int> > p[])

{

   int x, y;

   long long cost, minimumCost = 0;

   for(int i = 0;i < edges;++i)

   {

       // Selecting edges one by one in increasing order from the beginning

       x = p[i].second.first;

       y = p[i].second.second;

       cost = p[i].first;

       // Check if the selected edge is creating a cycle or not

       if(root(x) != root(y))

       {

           minimumCost += cost;

           union1(x, y);

       }    

   }

   return minimumCost;

}

int main()

{

   int x, y;

   long long weight, cost, minimumCost;

   initialize();

   cin >> nodes >> edges;

   for(int i = 0;i < edges;++i)

   {

       cin >> x >> y >> weight;

       p[i] = make_pair(weight, make_pair(x, y));

   }

   // Sort the edges in the ascending order

   sort(p, p + edges);

   minimumCost = kruskal(p);

   cout << minimumCost << endl;

   return 0;

}

8 0
3 years ago
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