Find the zeros of the polynomial x2-7please answer step by step

Mathematics

1 answer:

Yuki888 [10]2 years ago

6 0

Answer:

x = ± $\sqrt{7}$

Step-by-step explanation:

To find the zeros equate the polynomial to zero, that is

x² - 7 = 0 ( add 7 to both sides )

x² = 7 ( take the square root of both sides )

x = ± $\sqrt{7}$

Thus the exact solutions are

x = - $\sqrt{7}$ , x = $\sqrt{7}$

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Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are sum

IrinaK [193]

Answer:

0.84

Step-by-step explanation:

Given that Disks of polycarbonate plastic from a supplier are analyzed for scratch and shock resistance. The results from 100 disks are summarized as follows:

P(A) = 0.86, P(B) = 0.79, P(A') = 0.14, P(AUB) = 0.95

We are to find out P(A'UB)

We have

$P(AUB) =P(A)+P(B)-P(A\bigcap B)\\0.95=0.86+0.79-P(A\bigcap B)\\P(A\bigcap B)=0.70$

$P(A'UB) = P(A')+P(B)-P(A' \bigcap B)\\= 1-P(A) +P(B)-[P(B)-P(A \bigcap B)]\\= 1-0.86+0.79-P(B)+[tex]P(A'UB)=0.14+0.79-0.79+0.70\\=0.84$ P(A \bigcap B)[/tex]