v₀ = initial velocity of the freight train while it approach a road crossing = 16 km/h = 16 (5/18) m/s = 4.44 m/s
v = final velocity of the freight train after it crosses a road crossing = 65 km/h = 65 x 5/18 m/s = 18.06 m/s
t = time to do so = 10 min = 10 x 60 sec = 600 sec
acceleration is given as
a = (v - v₀ )/t
a = (18.06 - 4.44)/(600)
a = 0.023 m/s²
a = 294
Equation y=5x-2
500-2 =498
Answer:
c
Step-by-step explanation:
first, find the area of the rectangle thing,
A = lw
14 x 8
112
but, there is a semicircle in it so you need to subtract that from it:
A = πr^2/2
A = π(4)^2/2
A = π16/2
A = 8π
A ≈ 25.132741228718346
then subtract that area from the area of the rectangle:
112 - 25.132741228718346
86.867258771281654
or about 89.9
(24,18)(28,21)
slope(rate of change) = (21 - 18) / (28 - 24) = 3/4 <==
<em>so</em><em> </em><em>the</em><em> </em><em>right</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>of</em><em> </em><em>option</em><em> </em><em>C</em><em>.</em>
<em>Look</em><em> </em><em>at</em><em> </em><em>the</em><em> </em><em>attached</em><em> </em><em>picture</em><em> </em><em>⤴</em>
<em>Hope</em><em> </em><em>it</em><em> </em><em>will</em><em> </em><em>help</em><em> </em><em>u</em><em>.</em><em>.</em><em>.</em>
