I would approach the problem like this:
1 oz bottle.............................30cm^3
33 oz bottle.............................xcm^3
in a 33 oz bottle will be x=33*30=990cm^3
density=mm/v
13.6g/cm^3= m/ 990cm^3
m= 13.6 * 990=13464 g
or 13.464 kg in a 33 oz bottle
Answer:
17%
Step-by-step explanation:
3/17.95 = 0.167
0.167 × 100 = 16.7 *rounding to 17
12.95 × 0.17 = 3.0515
Answer:
x= HJ+27/7
Step-by-step explanation:
HJ + 27 = 7x
HJ+27/7 = x
We apply our knowledge in variation.
The solution can be seen in the photo
Answer:
Work individually or in teams of two to construct and launch paper rockets using a teacher-built PVC-pipe launcher.
Following the flight of their rocket, calculate the altitude their rocket achieved.
Based on the flight performance of their rockets, analyze their rocket designs, modify or rebuild them, launch again, and calculate the altitude achieved to determine if their changes affected the performance of the rocket.
Conclude the activity by writing a post-flight mission report.
Materials