Answer: See below
Step-by-step explanation:
27. -(a-3)
28. (b-1)(b+3)
29. (c+4)(c+5)
30. d(d+5)
31. -(3/4)(2e-5)
Sorry - I don't have time to enter the details. Look for areas where the expressions can be factored in a manner that forms as many equivalent expressions in both the numerator and denominator.
For example: In problem 30:
(5d-20)/(d^2+d-20) * [??]/20d = 1/4
Factor:
<u>(5(d-4))</u> <u>d(d+5)</u> = 1/4
(d-4)(d+5<u>)</u> 20d
The (d-4), d+5, and d terms cancel, leaving
5/20 = 1/4
Answer:
B
Step-by-step explanation:
Answer:
Working with proportional relationships allows one to solve many real-life problems such as adjusting a recipe, quantifying chance (odds and probability), scaling a diagram (drafting and architecture), and finding percent increase or percent decrease (price markup, discount, and tips).
Step-by-step explanation:
Hi there
x² + 7x = -10
x² + 7x + 10 = 0
Now, we can factor left side
(x+2)(x+5) = 0
Set factors equal to 0
x + 2 = 0 or x + 5 = 0
x = 0 - 2 or x = 0 - 5
x = -2 or x =-5
I hope that's help !
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