Answer:
Question 3 is- B. 8 ounces
Step-by-step explanation:
Answer:
A trapezoid has one pair of parallel sides and a parallelogram has two pairs of parallel sides. So a parallelograms are also trapezoids.
Answer:
Diameter of sphere = 18 cm
Step-by-step explanation:
<h2>Volume of Cylinder and Sphere:</h2><h3> Cylinder:</h3>
Diameter = 18 cm
r = 18÷ 2 = 9 cm
h = 12 cm

= π * 9 * 9 * 12 cm³
<h3>Sphere:</h3>

Solid cylinder is melted and turned into a solid sphere.
Volume of sphere = volume of cylinder

![\sf r^{3}= \dfrac{\pi *9*9*12*3}{4*\pi }\\\\ r^{3}=9 * 9 *3 *3\\\\\\r = \sqrt[3]{9*9*9}\\\\ r = 9 \ cm\\\\diameter = 9*2\\\\\boxed{diameter \ of \ sphere = 18 \ cm}](https://tex.z-dn.net/?f=%5Csf%20r%5E%7B3%7D%3D%20%5Cdfrac%7B%5Cpi%20%2A9%2A9%2A12%2A3%7D%7B4%2A%5Cpi%20%7D%5C%5C%5C%5C%20%20r%5E%7B3%7D%3D9%20%2A%209%20%2A3%20%2A3%5C%5C%5C%5C%5C%5Cr%20%3D%20%5Csqrt%5B3%5D%7B9%2A9%2A9%7D%5C%5C%5C%5C%20r%20%3D%209%20%5C%20cm%5C%5C%5C%5Cdiameter%20%3D%209%2A2%5C%5C%5C%5C%5Cboxed%7Bdiameter%20%5C%20of%20%5C%20%20sphere%20%3D%2018%20%5C%20cm%7D)
Answer:
3.1 gallons
Step-by-step explanation:
To solve this, we need to figure out how many gallons of gas go into 72 miles. We know 23 miles is equal to one gallon of gas, and given that the ratio of miles to gas stays the same, we can say that
miles of gas / gallons = miles of gas / gallons
23 miles / 1 gallon = 72 miles / gallons needed to go to Bob's mother's house
If we write the gallons needed to go to Bob's mother's house as g, we can say
23 miles / 1 gallon = 72 miles/g
multiply both sides by 1 gallon to remove a denominator
23 miles = 72 miles * 1 gallon /g
multiply both sides by g to remove the other denominator
23 miles * g = 72 miles * 1 gallon
divide both sides by 23 miles to isolate the g
g = 72 miles * 1 gallon/23 miles
= 72 / 23 gallons
≈ 3.1 gallons
C is not continuous.
Continuous functions have connected graphs; this indicates that every possible value of x has a value of y associated with it. In this case, that says that every possible radius measurement has a number of tennis balls associated with it. The problem with this is that we cannot have a fractional part of a tennis ball, so it is not continuous.