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4vir4ik [10]
2 years ago
12

Simplify 5 square root of 11 end root minus 12 square root of 11 end root minus 2 square root of 11. negative 33 square root of

9 negative 11 square root of 9 negative 9 square root of 11 negative 9 square root of 33
Mathematics
1 answer:
Alla [95]2 years ago
6 0
As long as your indexes are the same (which they are; they are all square roots) and you radicands are the same (which they are; they are all 11), then you can add or subtract.  The rules for adding and subtracting radicals are more picky than multiplying or dividing.  Just like adding fractions or combining like terms.  Since all the square roots are the same we only have to worry about the numbers outside.  In fact, it may help to factor out the sqrt 11: (5-12-2) \sqrt{11}.  The numbers subtract to give you -9.  Therefore, the simplification is -9 \sqrt{11}
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2+3+7+34+7000+12242534
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Step-by-step explanation:

add all the numbers:)

4 0
2 years ago
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Gnom [1K]

Answer:

3 sqrt 5

Step-by-step explanation:

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2 years ago
Can I get help with finding the Fourier cosine series of F(x) = x - x^2
trapecia [35]
Assuming you want the cosine series expansion over an arbitrary symmetric interval [-L,L], L\neq0, the cosine series is given by

f_C(x)=\dfrac{a_0}2+\displaystyle\sum_{n\ge1}a_n\cos nx

You have

a_0=\displaystyle\frac1L\int_{-L}^Lf(x)\,\mathrm dx
a_0=\dfrac1L\left(\dfrac{x^2}2-\dfrac{x^3}3\right)\bigg|_{x=-L}^{x=L}
a_0=\dfrac1L\left(\left(\dfrac{L^2}2-\dfrac{L^3}3\right)-\left(\dfrac{(-L)^2}2-\dfrac{(-L)^3}3\right)\right)
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Two successive rounds of integration by parts (I leave the details to you) gives an antiderivative of

\displaystyle\int(x-x^2)\cos nx\,\mathrm dx=\frac{(1-2x)\cos nx}{n^2}-\dfrac{(2+n^2x-n^2x^2)\sin nx}{n^3}

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4 0
3 years ago
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5000 square ft

Step-by-step explanation:

4 0
3 years ago
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STatiana [176]

Answer:

Option: C is the correct answer.

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We know that the graph of a cosecant function has a minimum value for a upward open curve as : 1

It could be seen from the graph.

But here the minimum value of the upward open curve in the transformed function is: -2

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-2-1=-3

This means that there is a vertical shift of 3 units down in the parent function.

4 0
2 years ago
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