Simplify 5 square root of 11 end root minus 12 square root of 11 end root minus 2 square root of 11. negative 33 square root of
1 answer:
As long as your indexes are the same (which they are; they are all square roots) and you radicands are the same (which they are; they are all 11), then you can add or subtract. The rules for adding and subtracting radicals are more picky than multiplying or dividing. Just like adding fractions or combining like terms. Since all the square roots are the same we only have to worry about the numbers outside. In fact, it may help to factor out the sqrt 11: 
. The numbers subtract to give you -9. Therefore, the simplification is 
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In a set of data, if the data is perfectly symmetrical then the mean is equal to the median. In this case, the median would be 50.
For example, consider the data set: {25, 50, 75}
The mean is going to be 50 because = 50
The median is also 50 because that is the middle number when ordered numerically.
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The term of the given quadratic sequence is found to be 3n² - n + 1 using the principle of mathematical induction.
Given,
In the question:
The quadratic sequence is :
3, 11, 25, 45, ...
To find the nth term of the quadratic sequence.
Now, According to the question;
The first term of the sequence is 3, the second term is 11, the third term is 25, and the fourth term is 45.
The difference between the first and second terms can be calculated as follows:
11-3 = 8
The difference between the second and third terms can be calculated as follows:
25-11 = 14
The difference between the third and fourth terms can be calculated as follows:
45-25 = 20
The sequence is expressed as follows:
3,3+8,11+11,25+20,...
The difference between consecutive terms expands by 6.
Use the principle of mathematical induction.
6
= 3n(n+1)
The sequence's nth term can be calculated as follows:
term = 3n(n+1) - 4n + 1
= 3n² - n + 1
Hence, the term of the given quadratic sequence is found to be 3n² - n + 1 using the principle of mathematical induction.
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