go to your profile click on picture and you can add one
Answer:
Based on statistical analysis the claim is of 3% of patients developing adverse reaction is valid and there is a drug problem
Step-by-step explanation:
Here we have
Percentage of patients that develop nausea em= 153/5783 *100 = 2.65 %
To test the hypothesis, we put our null hypothesis as
H₀: μ = 3%
Alternative hypothesis is then
Hₐ: μ < 3%
Therefore the test statistic is
P₀ = 0.03
= 0.0265
n = 5783
From the above we have our test statistic as -1.579 from which gives our p value as P = 0.057.
Therefore, as we have our P value less than the confidence level of 0.05, we therefore fail to reject the null hypothesis because there is sufficient statistical evidence that suggest that the proportion of patients who would have adverse reaction to the drug = 3%.
Let shirts be x and ties be y
3x+5y=$60 Equation 1 (Equation 1 will be denoted by *)
2x+3y=$39 Equation 2 (Equation 2 will be denoted by !)
*x2 6x + 10y = $120
!x3 6x + 9y = $117
*-! y = 120-117 =3
Ties are $3 each
Substitute this value back into one of the original 2 equations:
3x+5y=$60
3x+(5x3) = 60
3x+15=60
3x=45
x=15
Shirts are $15