Hoping to be named Salesperson of the Month, Luther called the names from 1/4 of a page of the phone book last week. This week,
1 answer:
You might be interested in
Answer:
The probability that an athlete chosen is either a football player or a basketball player is 56%.
Step-by-step explanation:
Let the athletes which are Football player be 'A'
Let the athletes which are Basket ball player be 'B'
Given:
Football players (A) = 13%
Basketball players (B) = 52%
Both football and basket ball players = 9%
We need to find probability that an athlete chosen is either a football player or a basketball player.
Solution:
The probability that athlete is a football player =
The probability that athlete is a basketball player =
The probability that athlete is both basket ball player and football player =
We have to find the probability that an athlete chosen is either a football player or a basketball player .
Now we know that;
Hence The probability that an athlete chosen is either a football player or a basketball player is 56%.
C. 4
Look at where segment A'B' intersects, at x = 8.
Look at where segment AB intersects, at x = 2.
AB is smaller then A'B' that means the scale factor is
.
Hope this helps.