5.4142 and <span>2.5858 are the numbers you need</span>
Answer:
20. 
22. 
24. 
Step-by-step explanation:
20. 
The GCF is x, so you group it out of the equation first.

Then, you find 2 numbers that will equal to 2 when you add them and will equal to -48 when you multiply them.

The two numbers would be -6 and 8. You then differentiate the squares.

22. 
The GCF is 2, so you must group it out.

Find the two numbers that will equal to 5 when you add them and will equal to 4 when you multiply them.

The two numbers would be 1 and 4. Finally, differentiate the squares.

24. 
The GCF is 5m, so you must group it out.

Find the two numbers that will equal to 6 when you add them and will equal to -7 when you multiply them.

The two numbers would be -1 and 7. Finally, differentiate the squares.

If you need area of the trapezoids:
Area of parallelogram = 10×7 = 70 sq. units
Area of each trapezoid = 1/2 × area of parallelogram = 1/2 × 70 = 35 sq. units
ANSWER:
The surface area of the star is 3.2700 x
square kilometres.
EXPLANATIONS:
Diameter of the star = 1.8083 x
Km.
Surface area of the star = 4
Where n is the radius of the star.
So that;
n =
= 0.90415 x 
n = 0.90415 x
Km
Thus,
Surface area = 4 x 
= 326994889
Surface area = 3.2700 x

Therefore, the surface area of the star is 3.2700 x
square kilometres.
Answer:
A
Step-by-step explanation: