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3 years ago

There are 4 tablespoons in cup. There are 2 cups in 1 pint. How many tablespoons are there in 1 pint?

Mathematics

2 answers:

Flauer [41]3 years ago

3 0

hi the answer is 32 tablespoons in a pint

Harrizon [31]3 years ago

3 0

Answer:

there are 32 tablespoons in 1 pint .

Step-by-step explanation:

beacause i asked siri .

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The Hartnett Corporation manufactures baseball bats with Pudge Rodriguez's autograph stamped on them. Each bat for $35 and has a

Verdich [7]

Answer:

Find the sales (in units) needed to earn a profit of $262,500

Step-by-step explanation:

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5 0

3 years ago

How many times greater is the value of the 2 in 204,936 than the value of the 2 in 124,936

miss Akunina [59]

10 times 20,000 equals 200,000. So the answer is C, the value of the 2 is 10 times greater

3 0

3 years ago

Bought three boxes totaling 151 book cost 50% more than the other two what was the price of the more expensive book 80 85 90 95

GenaCL600 [577]

Two cheaper books = x
more expensive = 1.5x
so, 2.5x=150
150/2.5=x=60
therefore the more expensive book = 90

7 0

3 years ago

11. ¿Es mayor 1/4 que 0.50? Justifica tu pregunta

musickatia [10]

Eh yo creo que no, si estoy mal los siento

3 0

3 years ago

We are standing on the top of a 320 foot tall building and launch a small object upward. The object's vertical altitude, measure

STALIN [3.7K]

Answer:

The highest altitude that the object reaches is 576 feet.

Step-by-step explanation:

The maximum altitude reached by the object can be found by using the first and second derivatives of the given function. (First and Second Derivative Tests). Let be $h(t) = -16\cdot t^{2} + 128\cdot t + 320$ , the first and second derivatives are, respectively:

First Derivative

$h'(t) = -32\cdot t +128$

Second Derivative

$h''(t) = -32$

Then, the First and Second Derivative Test can be performed as follows. Let equalize the first derivative to zero and solve the resultant expression:

$-32\cdot t +128 = 0$

$t = \frac{128}{32}\,s$

$t = 4\,s$ (Critical value)

The second derivative of the second-order polynomial presented above is a constant function and a negative number, which means that critical values leads to an absolute maximum, that is, the highest altitude reached by the object. Then, let is evaluate the function at the critical value:

$h(4\,s) = -16\cdot (4\,s)^{2}+128\cdot (4\,s) +320$

$h(4\,s) = 576\,ft$

The highest altitude that the object reaches is 576 feet.

6 0

4 years ago