Answer:
There is a 20% probability that the store selected does not violate the institute scanner accuracy standard
Step-by-step explanation:
70 company stores were investigared.
56 violated the institute's scanner accuracy standard.
70-56 = 14 did not violate the institute scanner accuracy standard.
If 1 of the 70 company stores is randomly selected, what is the probability that that store does not violate the institute scanner accuracy standard?
This is 14 divided by 70, so:
There is a 20% probability that the store selected does not violate the institute scanner accuracy standard
Answer:
g = At/60
Step-by-step explanation:
Given:
A = 60(g/t)
60(g/2) is a mistake in the question which the question has corrected in the comments)
A is the average for a professional hockey goalie.
g is the number of goals scored against the goalie.
t represents the time played in minutes.
Finding 'g':
A = 60(g/t)
can be written as A = (60*g)/t
Multiplying by 't' on both sides:
At = (60*g)*t/t
At = 60*g
Dividing by '60' on both sides:
At/60 = 60*g/60
At/60 = g
⇒ g = At/60
Not sure if there was supposed to be a list, but here is one expression that is equivalent. 2.2n+4. Since all I did was add like terms, I can come upon an equivalent expression.
Answer:
t = 4
Step-by-step explanation:
Given that:
When h(t) = 80, we have that:
t = 0 represents when the ball has not been thrown at all, in its initial position.
t = 4 represents the time taken for the ball to hit the roof of the building on its way down.
Hence, our answer is t = 4. (t is in secs)
Answer:
The 17th term in arithmetic sequence is 68
Step-by-step explanation:
The general formula of arithmetic sequence is:
aₙ = a₁ + (n – 1)d.
We are given a₆ = 101 and a₉ = 83 and we need to find a₁₇
To find the term a₁₇ we should know a₁ and d. So we would find both
a₆ = a₁ +(6-1)d
101 = a₁ +(5)d
101 = a₁ +5d eq(1)
and
a₉ = a₁ +(9-1)d
83 = a₁ + 8d eq(2)
Subtracting eq(2) from eq(1)
101 = a₁ +5d
83 = a₁ + 8d
- - -
__________
18 = -3d
=> d = 18/-3
=> d = -6
Putting value of d in eq(1)
101 = a₁ + 5d
101 = a₁ + 5(-3)
101 = a₁ -15
=> a₁ = 101+15
=> a₁ = 116
Now finding a₁₇:
aₙ = a₁ + (n – 1)d.
a₁₇ = 116 +(17-1)(-3)
a₁₇ = 116+(16)(-3)
a₁₇ = 116 - 48
a₁₇ = 68
So, the 17th term in arithmetic sequence is 68
