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allochka39001 [22]
3 years ago
9

50+10(8*1)+2 What property do you use to solve this and how.

Mathematics
2 answers:
MissTica3 years ago
7 0
You need to use PEMDAS
So first you do the parenthesis.
8*1=8.
So now re-write the problem.
50+10*8+2
Now you are going to multiply.
10*=80
Now re-write the problem again. 
10+80+2
10+80=90+2=92
So the answer to this problem is 92.
Sergio [31]3 years ago
7 0
You should use PEMDAS
(parenthesis, exponents, multiply, divide, add, and subtract)
you can remember it by using 
Please Excuse My Dear Aunt Sally
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Use the distributive property -5 {x + 4} + -3x + -9x + -7
grin007 [14]

Answer:

-17x - 27

Step-by-step explanation:

Distributive property is the multiplication of the number outside the parenthesis and the ones inside.

-5(x + 4) + -3x + -9x + -7

-5x - 20 + -3x + -9x + -7

Combine like terms:

-5x - 20 + -3x + -9x + -7

-5x +-3x

 -8x + -9x

      -17x

-17x - 20 + -7

     -20 + -7

         -27

The answer is -17x - 27

Hope this helped.

8 0
3 years ago
Choose the value that breaks this gem into 10 equal pieces
AnnyKZ [126]

Answer:

25 percent

Step-by-step explanation:

cuz am smart

7 0
3 years ago
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These are two similar triangles.<br> What does x equal?
tangare [24]

Answer:

112

Step-by-step explanation:

So, we know that a triangle's sides must add up to have a sum of 180. If you add up your given lengths and you should get 47, not including x. Then if you look at the left side/the one without a given length and it should be identical to the 21, so you know that side is 21. So now add 21 to 47, you should get 68. Finally, you subtract 68 from 180 like this: 180-68, and it should equal 112. So you're answer is 112.

3 0
2 years ago
Whats 5578 ÷ 68 equal to
kramer

5578/68=82.029411764705882352941176470588

that would be rounded  to 82.02 which is the answer

7 0
3 years ago
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Use the exponential decay​ model, Upper A equals Upper A 0 e Superscript kt​, to solve the following. The​ half-life of a certai
Akimi4 [234]

Answer:

It will take 7 years ( approx )

Step-by-step explanation:

Given equation that shows the amount of the substance after t years,

A=A_0 e^{kt}

Where,

A_0 = Initial amount of the substance,

If the half life of the substance is 19 years,

Then if t = 19, amount of the substance = \frac{A_0}{2},

i.e.

\frac{A_0}{2}=A_0 e^{19k}

\frac{1}{2} = e^{19k}

0.5 = e^{19k}

Taking ln both sides,

\ln(0.5) = \ln(e^{19k})

\ln(0.5) = 19k

\implies k = \frac{\ln(0.5)}{19}\approx -0.03648

Now, if the substance to decay to 78​% of its original​ amount,

Then A=78\% \text{ of }A_0 =\frac{78A_0}{100}=0.78 A_0

0.78 A_0=A_0 e^{-0.03648t}

0.78 = e^{-0.03648t}

Again taking ln both sides,

\ln(0.78) = -0.03648t

-0.24846=-0.03648t

\implies t = \frac{0.24846}{0.03648}=6.81085\approx 7

Hence, approximately the substance would be 78% of its initial value after 7 years.

5 0
3 years ago
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