Answer:
D. 1.3
Step-by-step explanation:
Perimeter (square) = 4*side
4 = 4*side
side = 1
We have triangle QVR. QV is a hypotenuse.
If we look at the triangle QTR, QT is a hypotenuse.
QV should be less than QT.
Let's find QT using Pythagorean theorem.
c² = a² + b²
QT² = QR² + RT² = 1² + 1² = 2
QT = √2 ≈ 1.4
QV < QT
QV < 1.4
We have 1.3 and 1 that are less than 1.4, but 1 is a length of a leg of the triangle, so 1 is impossible.
Answer D. 1.3
Can't see the graph, but it should look something like this:
The numbers in the chart are -7.1, -3.4, -1.2, 2.1, and 3.4. So, from greatest to least the numbers will be:
3.4, 2.1, -1.2, -3.4, and then -7.1.
With absolute value, the numbers from greatest to least are:
|7.1|, |3.4|, 3.4, 2.1, |1.2|.
However, this is assuming that Friday is 3.4, which was given information on the last question. Hope this helps!
Answer:
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