Answer:
Step-by-step explanation:
basically, what they are asking you is to factor and then plug in the values (x=3; x=4) that they gave you.
first, you need to factor out the equation.
start with the original equation.
V=4x^3+10x^2+4x
factored form:
V= 2x(2x^2+5x+2)
next, you're going to want to plug in the values.
the answer asks for x=4, but you should do both.
v=2(3)(2(3)^2+5(3)+2)
do not forget to do the exponents before!
v=6(18+15+2)
v=6(35)
v=210 ft^2
that's the answer for if x was equal to 3.
V= 2x(2x^2+5x+2)
<em>don't forget to write the original equation first. </em>
V=2(4)(2(4)^2+5(4)+2)
<em>V=8(36+20+2)</em>
<h2>
<u><em>V=464 ft^2 </em></u></h2>
⬆is your answer! hope this helped!!
1+9,2+8,3+7
1+9=10,2+8=10, fhdghdghhdsdasgsfgadg
Find the area of each shape and add.Let's start with the first semi-circle(half-circle)
If the area of a circle is πr² , then the area of a semi-circle is 1/2πr² where is 22/7 or 3.14, and r is the radius which is 1.8 meters
A=1/2πr²
A=1/2*22/7*1.8*1.8
A=5.09 m²(rounded to nearest hundredth)
Since the semi-circles are two and have the same radius, multiply the area of the first one by two or go through the same process again.
So 5.09 *2=10.18meters square is the area of the two semi-circles
Now, let's find the area of a rectangle which is length times width, where length is 6 meters and width is (1.8+1.8, because 1.8 is half the width)=3.6 meters
A=l*w
A=6*3.6
A=21.6meters square
Therefore the area of the shape is 10.18m²+21.6m²=219.888m²
Answer:
Option B. f¯¹(x) = ³√(– x – 9)
Step-by-step explanation:
From the question given above:
f(x) = – x³ – 9
f¯¹(x) =?
We can obtain the inverse f¯¹(x) of the above equation by doing the following:
f(x) = – x³ – 9
Replace f(x) with y
y = – x³ – 9
Interchange x and y
x = – y³ – 9
Make y the subject . This is illustrated below:
x = – y³ – 9
Rearrange
x + 9 = – y³
Multiply through by –1
–(x + 9) = y³
y³ = – x – 9
Take the cube root of both side
y = ³√(– x – 9)
Replace y with f¯¹(x)
f¯¹(x) = ³√(– x – 9)
Thus, the inverse of the function
f(x) = – x³ – 9
is
f¯¹(x) = ³√(– x – 9)