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lakkis [162]
2 years ago
14

Zelma buys p pounds of bananas for $0.40 per pound she pays the clerk with a $20 bill the clerk subtract the total cost of the b

ananas from the 20-dollar bill to determine the amount of change to give zelma which expression represents the amount of change zelma should receive
Mathematics
1 answer:
Sloan [31]2 years ago
7 0
You didnt include the (presumably) multiple choice answers. My guess is that the answer would be along the lines of: 20 - (P times .40)
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Of 30 students 1/3 play sports 2/3 of them play soccer. How many play soccer
agasfer [191]
1/3 of 30 is 10 because you dividing it by 3 and you would get 10.

Now 2/3 of 10 :

10/3=3.3 (2/3 so we have to multiply by 2) 3.3•2=6.6

6.6 has to be estimated because you can't have 6.6 people.

Your answer would be 6. Before I said 7 but you said I was incorrect so the only possibility left is 6.

Hoped I helped!
4 0
2 years ago
Read 2 more answers
Express the integral as a limit of Riemann sums. Do not evaluate the limit. (Use the right endpoints of each subinterval as your
Veronika [31]

The expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Given an integral \int\limits^5_b {1} \, x/(2+x^{3}) dx.

We are required to express the integral as a limit of Riemann sums.

An integral basically assigns numbers to functions in a way that describes displacement, area, volume, and other concepts that arise by combining infinite data.

A Riemann sum is basically a certain kind of approximation of an integral by a finite sum.

Using Riemann sums, we have :

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty}∑f(a+iΔx)Δx ,here Δx=(b-a)/n

\int\limits^5_1 {x/(2+x^{3}) } \, dx=f(x)=x/2+x^{3}

⇒Δx=(5-1)/n=4/n

f(a+iΔx)=f(1+4i/n)

f(1+4i/n)=[n^{2}(n+4i)]/2n^{3}+(n+4i)^{3}

\lim_{n \to \infty}∑f(a+iΔx)Δx=

\lim_{n \to \infty}∑n^{2}(n+4i)/2n^{3}+(n+4i)^{3}4/n

=4\lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3}

Hence the expression of integral as a limit of Riemann sums of given integral \int\limits^5_b {1} \, x/(2+x^{3}) dxis 4 \lim_{n \to \infty}∑n(n+4i)/2n^{3}+(n+4i)^{3} from i=1 to i=n.

Learn more about integral at brainly.com/question/27419605

#SPJ4

5 0
1 year ago
Using the Multiplication Property of -1
Papessa [141]

A. -(a+5)

Because the negative sign is outside the parenthesis, multiplying by -1 just removes the negative sign:

-(a+5) * -1 = a+5


B. -(-x+31)

Apply the distributive property:

-(-x+31) becomes (- -x +31) which simplifies to (x+31)

multiply that by -1 to get -x+31


C. -(4x+12)

Because the negative sign is outside the parenthesis, multiplying by -1 just removes the negative sign:

-(4x+12) * -1 = 4x+12

7 0
3 years ago
Solve the equation.
Vinil7 [7]
If you would like to solve the equation x + 1/6 = 6, you can do this using the following steps:

x + 1/6 = 6       /-1/6
x + 1/6 - 1/6 = 6 - 1/6
x = 6 - 1/6
x = 36/6 - 1/6
x = 35/6
x = 5 5/6

The correct result would be C. x = 5 5/6.
5 0
3 years ago
PLEASE HELP!!!<br> (9r^3 - 59r^2 - 30r + 7) / (r - 7)
Xelga [282]
Go to math papa it really helps

8 0
2 years ago
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