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Westkost [7]
3 years ago
9

The sides of a rectangle are 8cm and 6cm. What is the length of the diagonal. 12cm 10cm 9cm 7cm

Mathematics
2 answers:
tatiyna3 years ago
5 0

Answer:

10 cm

Step-by-step explanation:

The diagonal d divides the rectangle into 2 right triangles with legs 8 and 6 and hypotenuse d

Using Pythagoras' identity in one of the right triangles, then

d² = 8² + 6² = 64 + 36 = 100 ( take square root of both sides )

d = \sqrt{100} = 10 cm

Neko [114]3 years ago
5 0

Answer:

\huge\boxed{c = 10\ cm}

Step-by-step explanation:

<u><em>Using Pythagorean Theorem</em></u>

c^2 = a^2 + b^2

Where c is the length of diagonal, a and b are the length of the rest 2 sides

=> c^2 = 8^2+6^2

=> c^2 = 64 + 26

=> c^2 = 100

Taking sqrt on both sides

=> c = 10 cm

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*PLEASE ANSWER* What is the area of minor sector AOB?
scoray [572]
<h3>Answer: Approximately 13 square units (choice B)</h3>

===========================================================

Explanation:

The given reflex angle is 215 degrees. A reflex angle is anything over 180 degrees, but less than 360. Subtract 215 from 360 to get the measure of angle AOB

angle AOB = 360 - 215 = 145

angle AOB = 145 degrees

We'll use this later.

Now find the area of the full circle. Use the formula A = pi*r^2. The radius is r = sqrt(10) which can be found through the distance formula or the pythagorean theorem. You want to find the length of either OA or OB to get the radius.

The area of the circle is

A = pi*r^2

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This is the exact area of the full circle, but we want just a fractional portion of it. Specifically we want the pie slice that is formed by angle AOB

area of sector AOB = [ (angle AOB)/360 ] * (area of full circle)

area of sector AOB = (145/360)*10pi

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3 0
3 years ago
Find the sum of H.C.F and L.C.M of<br> 8 and 12
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Answer:

THe HCF is 4 and the LCM is 24. The sum of 24 and 4 is 28. The answer is 28.

Step-by-step explanation:

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12: 1, 2, 3, 4, 6, 12.

LCM:

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12: 12, 24, 36, 48

8 0
3 years ago
How do you tell whether the ratios form a proportion
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4             8
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6            12

cross multiply by multiplying 4 by 12 and 6 by 8.
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3 0
3 years ago
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