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3 years ago

PLATO:Find the missing term. If y = 1 + i, then y3 − 3y2 + ( ) − 1 = -i .

Mathematics

1 answer:

laila [671]3 years ago

3 0

Answer:

X= 6i

Step-by-step explanation:

We have the following equation:

y^3 - 3y^2 + X - 1 = -i (1),

where X is the missing term.

So, we know that y = 1 + i. Where i = sqrt(-1).

Substituting y = 1 + i in the equation (1):

(1 + i)^3 - 3(1 + i)^2 + X - 1 = -i

(1)^3 + 3(i)(1)^2 + 3(1)(i)^2 + (i)^3 - 3(1 + 2(1)(i) + (i)^2) + X - 1 = -i

Simplifying:

1 + 3i -3i - i - 3(1 + 2i -1) + X - 1 = -i

1 - i -6i + X - 1 = -i

-i - 6i + X = -i

- 6i + X = 0

X= 6i

So the missing term is X= 6i

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Incomplete question. However, let's assume this are feasible regions to consider:

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Remember, we substitute the points value for x, y in the objective function P = 2x + 1.5y.

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Solve. High school pre-cal

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Answer:

Answer: Quadrant 4

Step-by-step explanation:

Graph of Functions

Let's analyze the function

$\displaystyle y=\frac{x^2+3x}{x+1}$

To better understand the following analysis, we'll factor y

$\displaystyle y=\frac{x(x+3)}{x+1}$

For y to have points in the first quadrant, at least one positive value of x must produce one positive value of y. It's evident that any x greater than 0 will do. For example, x=1 will make y to be positive in the numerator and in the denominator, so it's positive

For y to have points in the second quadrant, at least one negative value of x must produce one positive value of y. We need two of the factors that are negative. It can be seen that x=-2 will make y as positive, going through the second quadrant.

For the third quadrant, we have to find at least one value of x who produces a negative value of y. We only need to pick a value of x that makes one or all the factors be negative. For example, x=-4 produces a negative value of y, so it goes through the third quadrant

Finally, the fourth quadrant is never reached by any branch because no positive value of x can produce a negative value of y.

Answer: Quadrant 4

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