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Yakvenalex [24]
3 years ago
7

A 21 foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on level ground if 14 f

oot from the base of the building. How high up the wall does the ladder reach
Mathematics
1 answer:
Evgesh-ka [11]3 years ago
5 0

Answer:

15.65 foot

Step-by-step explanation:

Pythagoras theorem can be used

a² + b² = c²

a being 14
b being unknown ( x )
c being 21

hence,

14² + x² = 21²
196 + x² = 441

x = √245  

  = 15.65 foot (answer)

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Answer:

f = 10, g = 4.8 cm

Step-by-step explanation:

Area of ABCE = 60 cm²

Area of ABCD = 48 cm²

So,

Area of ADE = 60-48

=> 12 cm²

Area of ADE = \frac{1}{2} (Base)(Height)

<u><em>Where Area = 12 cm², Base = 4 cm</em></u>

12 = \frac{1}{2}(4)(Height)

Height = 12-2

Height = 10 cm

Where Height is AD

So, AD = 10 cm

Also, <u><em>AD is parallel and equal to BC</em></u>(f)<u><em></em></u>

So,

f = 10 cm

<u><em>Now, Finding g</em></u>

Area of ABCD = Base * Height

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Answer:

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