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Yakvenalex [24]
2 years ago
7

A 21 foot ladder is placed against a vertical wall of a building, with the bottom of the ladder standing on level ground if 14 f

oot from the base of the building. How high up the wall does the ladder reach
Mathematics
1 answer:
Evgesh-ka [11]2 years ago
5 0

Answer:

15.65 foot

Step-by-step explanation:

Pythagoras theorem can be used

a² + b² = c²

a being 14
b being unknown ( x )
c being 21

hence,

14² + x² = 21²
196 + x² = 441

x = √245  

  = 15.65 foot (answer)

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3 years ago
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3 years ago
One number is 7 more than another. The difference between their squares is 161. What are the numbers?
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now, we know one of them is 7 more than the other, so hmmm let's say "b" is 7 more than "a", so b = a + 7

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\bf a^2-b^2=161\qquad b=a+7\implies a^2-(a+7)^2=161
\\\\\\
a^2-(a^2+14a+49)=161\implies \underline{a^2-a^2}-14a-49=161
\\\\\\
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