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svp [43]
3 years ago
6

−7/2÷7/5 i do not get it PLZ HELP!!! ASAP

Mathematics
1 answer:
yulyashka [42]3 years ago
4 0
Okay, to start, when dividing fractions, one thing I use is to flip the numerator and denominator of the divisor and change the division sign to a multiplication sign so it would look like this: 
-7/2*5/7
Then, you would multiply straight across and you would get -35/14 which simplifies to -5/2.

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Please calculate this limit <br>please help me​
Tasya [4]

Answer:

We want to find:

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n}

Here we can use Stirling's approximation, which says that for large values of n, we get:

n! = \sqrt{2*\pi*n} *(\frac{n}{e} )^n

Because here we are taking the limit when n tends to infinity, we can use this approximation.

Then we get.

\lim_{n \to \infty} \frac{\sqrt[n]{n!} }{n} = \lim_{n \to \infty} \frac{\sqrt[n]{\sqrt{2*\pi*n} *(\frac{n}{e} )^n} }{n} =  \lim_{n \to \infty} \frac{n}{e*n} *\sqrt[2*n]{2*\pi*n}

Now we can just simplify this, so we get:

\lim_{n \to \infty} \frac{1}{e} *\sqrt[2*n]{2*\pi*n} \\

And we can rewrite it as:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n}

The important part here is the exponent, as n tends to infinite, the exponent tends to zero.

Thus:

\lim_{n \to \infty} \frac{1}{e} *(2*\pi*n)^{1/2n} = \frac{1}{e}*1 = \frac{1}{e}

7 0
3 years ago
Simplify the expression: 2 = (a + 5) =​
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Answer:

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Step-by-step explanation:

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What could be the length of the base of the scaled copy of the triangle?

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iren2701 [21]

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Step-by-step explanation:


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What is the volume of a cube whose edges each have a measure of 1.5 cm?
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Read 2 more answers
for an art project student needs to cover a shoebox with construction paper the shoe box has a length of 14 inches a width of 7
elixir [45]

Answer:

14×7×5=490 i am not sure the answer

4 0
2 years ago
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