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3 years ago

Find the equation of the linear function 'g' going through (20,5) and (-5,-8). Use 'u' for your input variable.

Mathematics

1 answer:

frosja888 [35]3 years ago

3 0

Answer:

See below

Step-by-step explanation:

Use the slope-intercept form, which will be in this case:

g(u) = mu + b, where m is the slope, b is the y- intercept

Find the slope:

$m=(y_2-y_1)/(x_2-x_1)$
$m=(-8-5)/(-5-20)=(-13)/(-25)=13/25$

Find the value of the y-intercept:

$5=1/25*20+b$
$b=5-4/5=21/5$

The equation is:

$g(u)=\frac{13}{25} u+\frac{21}{5}$

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m_a_m_a [10]

Answer:31/40

Step-by-step explanation:

To add you have to have a common denominator. To get that you can multiply each fraction by one in different ways. 2/5 *8/8= 16/40 and 3/8* 5/5= 15/40 and then add those two to give you 31/40.

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3 years ago

Is 1.2 less than or higher than 1.5

Olenka [21]

1.2 is less than 1.5

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3 years ago

Lim t^4 - 6 / 2t^2 - 3t + 7

Harman [31]

I think you meant to say

$\displaystyle \lim_{t\to2}\frac{t^4-6}{2t^2-3t+7}$

(as opposed to x approaching 2)

Since both the numerator and denominator are continuous at t = 2, the limit of the ratio is equal to a ratio of limits. In other words, the limit operator distributes over the quotient:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)}$

Because these expressions are continuous at t = 2, we can compute the limits by evaluating the limands directly at 2:

$\displaystyle \lim_{t\to2} \frac{t^4 - 6}{2t^2 - 3t + 7} = \frac{\displaystyle \lim_{t\to2}(t^4-6)}{\displaystyle \lim_{t\to2}(2t^2-3t+7)} = \frac{2^4-6}{2\cdot2^2-3\cdot2+7} = \boxed{\frac{10}9}$

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3 years ago