What is x-10= -3 what is "x"?

Mumz [18]

Put the 50.605 over 1 then multiply by 1 to eliminate the decimal then multiply the numerator and denominator by 10^3=1000. Find the GCF which is 5 and divide the numerator and denominator by 5 then simplify the improper fraction

4 0

3 years ago

The total price of a shirt and a cap is $11. If the price of the shirt was doubled and the price of the cap was three times its

shusha [124]

Answer:

the shirt is 8 dollars and the cap is 3

Step-by-step explanation:

This is because 8 times 2 is 16 which is the new price of the shirt then 3 times 3 is 9 which would be the new cap price and 16 plus 9 is 25

4 0

2 years ago

There are 50 students in the 5th grade at Clark School. One day, 20% of them were absent. How many fifth graders were in school

natita [175]

Well, 20% is equivalent to (1/5). So, you'd put 50 in the numerator and 5 in the denominator. (50/5) is equal to 10. Then you'd take that value and subtract it from your original value. [ 50 - 10 = 40 ]. 40 Students were at school that day.

5 0

4 years ago

Which expression is a cube root of -1+i√3?

Tpy6a [65]

Answer:

<em>The correct option is C.</em>

Step-by-step explanation:

<u>Root Of Complex Numbers</u>

If a complex number is expressed in polar form as

$Z=(r,\theta)$

Then the cubic roots of Z are

$\displaystyle Z_1=\left(\sqrt[3]{r},\frac{\theta}{3}\right)$

$\displaystyle Z_2=\left(\sqrt[3]{r},\frac{\theta}{3}+120^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{r},\frac{\theta}{3}+240^o\right)$

We are given the complex number in rectangular components

$Z=-1+i\sqrt{3}$

Converting to polar form

$r=\sqrt{(-1)^2+(\sqrt{3})^2}=2$

$\displaystyle tan\theta=\frac{\sqrt{3}}{-1}=-\sqrt{3}$

It's located in the second quadrant, so

$\theta=120^o$

The number if polar form is

$Z=(2,120^o)$

Its cubic roots are

$\displaystyle Z_1=\left(\sqrt[3]{2},\frac{120^o}{3}\right)=\left(\sqrt[3]{2},40^o\right)$

$\displaystyle Z_2=\left(\sqrt[3]{2},40^o+120^o\right)=\left(\sqrt[3]{2},160^o\right)$

$\displaystyle Z_3=\left(\sqrt[3]{2},40^o+240^o\right)=\left(\sqrt[3]{2},280^o\right)$

Converting the first solution to rectangular coordinates

$z_1=\sqrt[3]{2}(\ cos40^o+i\ sin40^o)$

The correct option is C.

8 0

4 years ago

One pound of swordfish costs as much as 1.5 pounds of salmon. Mrs. O pays $39 for 2 pounds of salmon and 3 pounds of swordfish.

Dimas [21]

Answer:

The ratio of the amount for swordfish to the amount of salmon is 6:4

Step-by-step explanation:

Given as :

The price for 1 pound of swordfish = The price of 1.5 pound of salmon

So, On this relation

The price for ( 1 × 2 ) pound of swordfish = The price of ( 1.5× 2 ) pound of salmon

i.e The price for 2 pound of swordfish = The price of 3 pound of salmon

Now According to question

Mrs. O pay the total money for 2 pounds of swordfish and 3 pound of salmon = $ 39

Let the money she pay for swordfish = 2 sw

And The money she pay for salmon = 3 sa

∵, The total money she pay for both = $ 39

I.e 2 sw + 3 sa = 39

As 2 sw = 3 sa

So, 3 sa + 3 sa = 39

Or, 6 sa = 39

or, sa = $\frac{39}{6}$ = $\frac{13}{2}$

∴ sw = $\frac{13}{2}$ × $\frac{3}{2}$

or, sw = $\frac{39}{4}$

Now, the ratio of the amount for swordfish to the amount of salmon = $\frac{\frac{39}{4}}{\frac{13}{2}}$

I.e The ratio = $\frac{6}{4}$

Hence The ratio of the amount for swordfish to the amount of salmon is 6:4

Answer

3 0

3 years ago