Help pls thank you<3

Mathematics

1 answer:

SpyIntel [72]3 years ago

5 0

Answer:

$x$

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Since, 12² = 144 and 13² = 169, the square root of 150 is between 12 and 13.

Then, you can pick any two whole numbers less than 13 and multiple them by 1/8.

Remember that multiplying by 1/8 is the same that dividing by 8.

Choose 12 and 11, for instance, and two rational numbers that are less than 1/8 of the actual side length are 12/8 and 11/8.

12/8 can be simplified to 3/2 and 11/8 is in its simplest form.

Thus, two rational numbers that are within 1/8 of the actual side length of the bulletin board are 3/2 and 11/8.

Step-by-step explanation:

You might be interested in

Solve the following equation: 10 = -4 x

defon

I think it's x= -2.5

10/-4= -4x/-4

You need to get x by itself so you need to divide 4 in each side . Shown above

5 0

3 years ago

Help with 30 please. thanks.

Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

$\displaystyle y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}$

And we want to show that:

$\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}$

Instead of differentiating directly, we can first square both sides:

$\displaystyle y^2 = 3e^{2x} -4x + 1$

We can find the first derivative through implicit differentiation:

$\displaystyle 2y \frac{dy}{dx} = 6e^{2x} -4$

Hence:

$\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}$

And we can find the second derivative by using the quotient rule:

$\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}$