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2 years ago

14

At a pet store, Davina counted 12 parrots out of 20 birds. Which is an equivalent ratio of parrots to birds at the pet store? 2:

3 3 to 2 StartFraction 5 Over 3 EndFraction 3 to 5

2 answers:

Mazyrski [523]2 years ago

3 0

Answer:

3 to 2

Hope it helps xD

RUDIKE [14]2 years ago

3 0

Answer:

its B pls give brainleist

Step-by-step explanation:

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weqwewe [10]

Answer:

The y-intercept is –2.

The slope is Negative three-fifths

Step-by-step explanation:

I got it right on edge

3 0

2 years ago

What is the diagnosis of a rectangular room which measures 16 feet by 7 feet

Verizon [17]

The area would be 112 feet
The circumference would be 46feet

4 0

2 years ago

24) What is 35% of 125?

SCORPION-xisa [38]

35% = 0.35
0.35*125=43.75=answer
Alternate way to find answer
1.25*35=43.75

8 0

2 years ago

Read 2 more answers

Given the quadratic function f(x) = 4x^2 - 4x + 3, determine all possible solutions for f(x) = 0

solong [7]

Answer:

The solutions to the quadratic function are:

$x=i\sqrt{\frac{1}{2}}+\frac{1}{2},\:x=-i\sqrt{\frac{1}{2}}+\frac{1}{2}$

Step-by-step explanation:

Given the function

$f\left(x\right)\:=\:4x^2\:-\:4x\:+\:3$

Let us determine all possible solutions for f(x) = 0

$0=4x^2-4x+3$

switch both sides

$4x^2-4x+3=0$

subtract 3 from both sides

$4x^2-4x+3-3=0-3$

simplify

$4x^2-4x=-3$

Divide both sides by 4

$\frac{4x^2-4x}{4}=\frac{-3}{4}$

$x^2-x=-\frac{3}{4}$

Add (-1/2)² to both sides

$x^2-x+\left(-\frac{1}{2}\right)^2=-\frac{3}{4}+\left(-\frac{1}{2}\right)^2$

$x^2-x+\left(-\frac{1}{2}\right)^2=-\frac{1}{2}$

$\left(x-\frac{1}{2}\right)^2=-\frac{1}{2}$

$\mathrm{For\:}f^2\left(x\right)=a\mathrm{\:the\:solutions\:are\:}f\left(x\right)=\sqrt{a},\:-\sqrt{a}$

solving

$x-\frac{1}{2}=\sqrt{-\frac{1}{2}}$

$x-\frac{1}{2}=\sqrt{-1}\sqrt{\frac{1}{2}}$ ∵ $\sqrt{-\frac{1}{2}}=\sqrt{-1}\sqrt{\frac{1}{2}}$

as

$\sqrt{-1}=i$

so

$x-\frac{1}{2}=i\sqrt{\frac{1}{2}}$

Add 1/2 to both sides

$x-\frac{1}{2}+\frac{1}{2}=i\sqrt{\frac{1}{2}}+\frac{1}{2}$

$x=i\sqrt{\frac{1}{2}}+\frac{1}{2}$

also solving

$x-\frac{1}{2}=-\sqrt{-\frac{1}{2}}$

$x-\frac{1}{2}=-i\sqrt{\frac{1}{2}}$

Add 1/2 to both sides

$x-\frac{1}{2}+\frac{1}{2}=-i\sqrt{\frac{1}{2}}+\frac{1}{2}$

$x=-i\sqrt{\frac{1}{2}}+\frac{1}{2}$

Therefore, the solutions to the quadratic function are:

$x=i\sqrt{\frac{1}{2}}+\frac{1}{2},\:x=-i\sqrt{\frac{1}{2}}+\frac{1}{2}$

4 0

2 years ago

Help me please :/// help

gayaneshka [121]

It’s not scaled. You can see it’s not the same shape as image A. 1 is only added to the height. If a shape is scaled, then the shape will remain the same, however it’s size will not. Therefore, the answer is “not a scaled copy of image A because 1 is added to the height”

7 0

2 years ago

Read 2 more answers