You deposit $300 in an account earning 4% interest compounded annually. How much will you have

A company has beginning inventory of 20000, purchases of 15000, and ending of 2500. The cost of goods available for sale is?

motikmotik

Answer:

Maybe,2500. Is just my guessing.

4 0

3 years ago

Read 2 more answers

B. How was the original $20,000 investment split between the two interest rates?

Roman55 [17]

Answer:

t + f = 2000

let represent the amount invested at three percent; let f represent the amount invested at five percent. The total of these amounts is $20,000. The total of the interest earned by each amount is $800. Of course the interest earned is the amount multiplied by the interest rate.

4 0

2 years ago

Write the equation in the form Ax + By = C. Find an equation of a line passing through the pair of points (-7,3) and (-8,-9).

Illusion [34]

Answer:

12x -y = -87

Step-by-step explanation:

You can start with the 2-point form of the equation of a line and manipulate it to give you the standard form.

y = (y2 -y1)/(x2 -x1)(x -x1) +y1

y = (-9 -3)/(-8 -(-7))(x -(-7)) +3

y = (-12/-1)(x +7) +3

y = 12x +84 +3

-12x +y = 87 . . . . . subtract the x-term

12x -y = -87 . . . . . . make the leading coefficient positive (per standard form)

3 0

3 years ago

How do I find the domain range and function of the graph

Allisa [31]

Answer:

D = {-3, -2, -1, 1, 4}

R = {-5, -1, 0, 2}

Step-by-step explanation:

You have correctly described the process of finding the domain and range by the way you filled in the blanks at the top of the sheet.

__

The domain is the set of x-values of the points on the graph:

D = {-3, -2, -1, 1, 4}

The range is the set of (unique) y-values of the points on the graph:

R = {-5, -1, 0, 2}

3 0

1 year ago

The scale on a map is 1: 75 000. (a) Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

finlep [7]

Answer:

a. 1 200 000 km

b. 0.000 773 cm

c. 67 500 000 000 km²

d. 0.000 000 016 cm²

Step-by-step explanation:

a. Calculate the ACTUAL distance, in km, between two places which are 16 cm apart on the map.

Since the scale is 1 : 75000 that is 1 cm : 75000 km, we want to find the actual distance of 16 cm on the map. Let x be the actual distance in km.

So, 1 cm : 75000 km = 16 cm : x km

So, 1 cm/75000 km = 16 cm/x km

Thus x km = 16 cm × 75000 km/1 cm = 1 200 000 km

(b) Calculate length of a road on the map which is 0.58 km.

Let y be the length of road on the map. So, using our scale

1 cm : 75000 km = y cm : 0.58 km

So, 1 cm/75000 km = y cm/0.58 km

Thus y cm = 0.58 km × 1 cm/75000 km = 0.000 773 cm

(c) Calculate, in km², the ACTUAL area of a lake which is 12 cm2 on the map.

Since the scale is 1 : 75000 , the scale for the area would be the square of this. So, 1² : 75000² = 1 : 5 625 000 000 which is 1 cm² : 5 625 000 000 km²

Let z be the actual area of the lake.

So, 1 cm² : 5 625 000 000 km² = 12 cm² : z km²

So, 1 cm²/5 625 000 000 km² = 12 cm²/z km²

Thus z km² = 12 cm² × 5 625 000 000 km²/1 cm² = 67 500 000 000 km²

(d) Calculate the area of a play field on the map which has has an actual area of 90 km².

Let a represent the area of the play field on the map. Using our scale for the area,

1 cm² : 5 625 000 000 km² = a cm² : 90 km²

So, a cm² = 90 km² × 1/5 625 000 000 km² = 0.000 000 016 cm²

4 0

2 years ago